我对当前查询有问题,我希望获得基于列的记录/结果(示例列Status对于查询i具有new/pending/completed的值如果有3个状态为new的记录,则执行该操作,它应该过滤为只显示1个状态为new的记录)。下面是我目前的查询获得重复列。查询选择基于列的不同值的行
select a.CW_UPD_TMS,
case when a.CW_CRT_UID='AAA' then 'BBB'
else a.CW_CRT_UID end as CW_CRT_UID,
COALESCE(b.CW_S_BR, a.CW_S_BR) as CW_S_BR,
a.CW_TRX_STAT as STATUS,
SUBSTR(a.CW_UPD_TMS,7,2) as day,
SUBSTR(a.CW_UPD_TMS,5,2) as month,
SUBSTR(a.CW_UPD_TMS,1,4) as ayear,
SUBSTR(a.CW_UPD_TMS,9,2) as hours,
SUBSTR(a.CW_UPD_TMS,11,2) as mins,
SUBSTR(a.CW_UPD_TMS,13,2) as secs,
case when cast(SUBSTR(a.CW_UPD_TMS,9,2) as INT) > 12 then 'PM'
else 'AM' end as zone
from TABLEA a
left outer join TABLEB b on a.CW_CRT_UID = b.CW_S_USR
where a.CW_TRX_ID = '20150415110000798'
union
select a.CW_UPD_TMS,
case when a.CW_CRT_UID='AAA' then 'BBB'
else a.CW_CRT_UID end as CW_CRT_UID,
COALESCE(b.CW_S_BR, a.CW_S_BR) as CW_S_BR,
a.CW_TRX_STAT as STATUS,
SUBSTR(a.CW_UPD_TMS,7,2) as day,
SUBSTR(a.CW_UPD_TMS,5,2) as month,
SUBSTR(a.CW_UPD_TMS,1,4) as ayear,
SUBSTR(a.CW_UPD_TMS,9,2) as hours,
SUBSTR(a.CW_UPD_TMS,11,2) as mins,
SUBSTR(a.CW_UPD_TMS,13,2) as secs,
case when cast(SUBSTR(a.CW_UPD_TMS,9,2) as INT) > 12 then 'PM'
else 'AM' end as zone
from TABLEC a
left outer join TABLEB b on a.CW_CRT_UID = b.CW_S_USR
where a.CW_TRX_ID = '20150415110000798'
这是当前的结果:
CW_UPD_TMS CW_CRT_UID CW_S_BR STATUS DAY MONTH AYEAR HOURS MINS SECS ZONE
2015062610260746811 happy KLC NEW 26 06 2015 10 26 07 AM
2015062610273984711 happy KLC NEW 26 06 2015 10 27 39 AM
2015062610275762511 happy KLC NEW 26 06 2015 10 27 57 AM
所以现在如何更改查询,以便只显示1只记录(秀分钟(CW_UPD_TMS))作为现在3记录有相同的状态(新)。
我预期的结果应该是:
CW_UPD_TMS CW_CRT_UID CW_S_BR STATUS DAY MONTH AYEAR HOURS MINS SECS ZONE
2015062610260746811 happy KLC NEW 26 06 2015 10 26 07 AM
对不起我的英文不好。
您不必指定DISTINCT,当你做一个UNION,因为UNION会删除重复的行。 – jarlh
因此,如果他们并不都具有相同的状态,那么您仍然希望看到那些行保持每个组中具有最早时间戳的行? – shawnt00
不要将日期或时间戳存储为字符,请使用DATE或TIMESTAMP数据类型! – jarlh