2017-07-17 53 views
1

我正尝试使用Sendgrid发送密码重置电子邮件。将Sendgrid集成到Google App Engine中

以下是错误的堆栈跟踪:

Traceback (most recent call last): 
    File "C:\Program Files\Google\google_appengine\lib\webapp2- 
2.5.2\webapp2.py", line 1535, in __call__ 
    rv = self.handle_exception(request, response, e) 
    File "C:\Program Files\Google\google_appengine\lib\webapp2- 
2.5.2\webapp2.py", line 1529, in __call__ 
    rv = self.router.dispatch(request, response) 
    File "C:\Program Files\Google\google_appengine\lib\webapp2- 
2.5.2\webapp2.py", line 1278, in default_dispatcher 
    return route.handler_adapter(request, response) 
    File "C:\Program Files\Google\google_appengine\lib\webapp2- 
2.5.2\webapp2.py", line 1102, in __call__ 
    return handler.dispatch() 
    File "C:\Program Files\Google\google_appengine\lib\webapp2- 
2.5.2\webapp2.py", line 572, in dispatch 
    return self.handle_exception(e, self.app.debug) 
    File "C:\Program Files\Google\google_appengine\lib\webapp2- 
2.5.2\webapp2.py", line 570, in dispatch 
    return method(*args, **kwargs) 
    File "C:\Users\C\PycharmProjects\alpha\u\user.py", line 121, in post 
    response = sg.client.mail.send.post(request_body=mail.get()) 
    File "C:\Users\C\PycharmProjects\alpha\python_http_client\client.py", 
line 227, in http_request 
    return Response(self._make_request(opener, request)) 
    File "C:\Users\C\PycharmProjects\alpha\python_http_client\client.py", 
line 161, in _make_request 
    raise exc 
UnauthorizedError 

我已经进口都sendgrid和python-HTTP客户端在我的项目。 (我为什么要导入这个分开?)

这里从Sendgrid演示了我的测试代码:

class PasswordResetHandler(BaseHandler): 
""" 
handler to reset the users password. 
also to verify if the user email is in the database 
""" 
def post(self): 
    email = self.request.get("email_for_reset") 

    sg = sendgrid.SendGridAPIClient(apikey=os.environ.get(SENDGRID_API_KEY)) 
    from_email = Email("[email protected]") 
    to_email = Email(email) 
    subject = "Sending with SendGrid is Fun" 
    content = Content("text/plain", "and easy to do anywhere, even with Python") 
    mail = Mail(from_email, subject, to_email, content) 
    response = sg.client.mail.send.post(request_body=mail.get()) 
    self.redirect('/u/password-reset-confirmation') 

任何人都可以对什么是怎么回事帮助吗?

谢谢。

回答

0

我使用的语法是不同的,使用SendGridClient

sg = sendgrid.SendGridClient(SENDGRID_API_KEY) 

message = sendgrid.Mail(
    to =   to, 
    subject =  subject, 
    html =   html, 
    text =   body, 
    from_email = sender 
) 

status, msg = sg.send(message) 
+0

感谢GAEfan,我应该明确表示我正在尝试集成Web API v3。这是SMTP中继代码,我也一样。融入项目要简单得多。 – zmdc

0

检查拼写错误您的API密钥,并确保它与os.environ.get()正确加载。

你得到HTTP错误401,你可以看到一个包含in the client.py code_make_request上线161(并导致它的行),您获得的是正在线159处理引发HTTPError:

exc = handle_error(err) 

handle_error()实施in exceptions.py,并且显示UnauthorizedError来自HTTPError 401.最可能的原因是api密钥不好。检查您的API密钥是否有错别字。我可以通过在我的代码中插入一个错误的api密钥来获得相同的HTTP错误。除此之外,我有这个功能与您在问题中显示的相同代码一起工作。

+0

谢谢你,我检查了API密钥。 – zmdc

+0

尝试将SENDGRID_API_KEY放在引号中,如快速入门所示:https://app.sendgrid.com/guide/integrate/langs/python。所以它看起来像'sg = sendgrid.SendGridAPIClient(apikey = os.environ.get('SENDGRID_API_KEY'))' –