1

服务器:Tomcat的7
春:第4版
Spring Security的版本3.25
Tuckey:4.0.3
春Tuckey URLRewriter的StackOverflow异常

我想使用tuckey URL重写,在我的Spring应用程序为了更好地支持angularjs html5mode。

我想将任何请求转发到/如果request-uri不是/ api或/ socket。如果请求是/ api或/ socket,我希望他们通过spring和dispather servlet并应用spring web安全。

这里是我webintializer类: 公共类ApplicationInitializer实现WebApplicationInitializer {

@Override 
public void onStartup(ServletContext servletContext) throws ServletException { 

    AnnotationConfigWebApplicationContext rootContext = new AnnotationConfigWebApplicationContext(); 
    rootContext.register(PersistenceConfig.class, WebSecurityConfig.class); 

    servletContext.addListener(new ContextLoaderListener(rootContext)); 

    AnnotationConfigWebApplicationContext webContext = new AnnotationConfigWebApplicationContext(); 
    webContext.register(ApplicationConfig.class); 

    AnnotationConfigWebApplicationContext socketContext = new AnnotationConfigWebApplicationContext(); 
    webContext.register(WebSocketConfig.class); 

    ServletRegistration.Dynamic restApi = servletContext.addServlet("rest-api", new DispatcherServlet(webContext)); 
    restApi.setLoadOnStartup(1); 
    restApi.addMapping("/api"); 

    ServletRegistration.Dynamic webSocket = servletContext.addServlet("web-socket", new DispatcherServlet(socketContext)); 
    webSocket.setLoadOnStartup(1); 
    webSocket.addMapping("/socket"); 

    Dynamic springSecurityFilter = servletContext.addFilter(AbstractSecurityWebApplicationInitializer.DEFAULT_FILTER_NAME, DelegatingFilterProxy.class); 
    springSecurityFilter.addMappingForUrlPatterns(EnumSet.allOf(DispatcherType.class), false, "/api/*"); 
    springSecurityFilter.addMappingForUrlPatterns(EnumSet.allOf(DispatcherType.class), false, "/socket/*"); 

    UrlRewriteFilter urlRewriteFilter = new UrlRewriteFilter(); 
    Map<String, String> urlRewriteFilterParams = new HashMap<String, String>(); 
    urlRewriteFilterParams.put("confReloadCheckInterval", "0"); 
    urlRewriteFilterParams.put("confPath", "/WEB-INF/classes/urlrewrite.xml"); 
    urlRewriteFilterParams.put("statusEnabled", "true"); 
    urlRewriteFilterParams.put("logLevel", "DEBUG"); 
    urlRewriteFilterParams.put("statusEnabledOnHosts", "localhost"); 

    Dynamic tuckeyRewriteFilter = servletContext.addFilter("UrlRewriteFilter", urlRewriteFilter); 
    tuckeyRewriteFilter.addMappingForUrlPatterns(EnumSet.of(DispatcherType.REQUEST, DispatcherType.FORWARD), false, "/*"); 
    tuckeyRewriteFilter.setInitParameters(urlRewriteFilterParams); 

} 
} 

的重写是越来越拾起,因为我可以到本地主机:8080 /重写状态和我的配置是存在的页面说它应该做我想做的事情。

我Tuckey UrlRewrite.XML文件如下:

<!DOCTYPE urlrewrite 
    PUBLIC "-//tuckey.org//DTD UrlRewrite 4.0//EN" 
    "http://www.tuckey.org/res/dtds/urlrewrite4.0.dtd"> 

<urlrewrite default-match-type="wildcard"> 
    <rule> 
     <condition type="request-uri" operator="notequal">/api/**</condition> 
     <condition type="request-uri" operator="notequal">/socket/**</condition> 
     <from>/**</from> 
     <to type="forward">/$1</to> 
    </rule> 
</urlrewrite> 

我得到的错误如下。这似乎是某种内在某种地方的递归性。如果我删除了tuckey,一切正常 线程“http-bio-8080-exec-1”中的异常java.lang.StackOverflowError at org.apache.catalina.core.ApplicationHttpRequest.setAttribute(ApplicationHttpRequest.java:281) at org .apache.catalina.core.ApplicationHttpRequest.setAttribute(ApplicationHttpRequest.java:281) at org.apache.catalina.core.ApplicationHttpRequest.setAttribute(ApplicationHttpRequest.java:281) at org.apache.catalina.core.ApplicationHttpRequest.setAttribute (ApplicationHttpRequest.java:281) 在org.apache.catalina.core.ApplicationHttpRequest.setAttribute(ApplicationHttpRequest.java:281)

回答

2

DispatcherType.FORWARD在过滤器定义是导致规则是适当的递归地递归自己。使用URL重写过滤器时,您只需将其映射到REQUEST即可。

希望可以帮到