从表格视图中的文本字段获取文本

Question

我在我的表格视图中有几行，每个行都是我的自定义单元类的一个实例，它包含单个UTextField。我为每个标签分配了一个标签，但我需要知道如何检索每个文本字段的文本值并将值分配给适当的字符串。

override func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell { 
     let cell = tableView.dequeueReusableCellWithIdentifier("paymentCell", forIndexPath: indexPath) as! PaymentInfoCell 

     cell.selectionStyle = .None 
     cell.textField.delegate = self 

     if indexPath.section == 0 { 
      cell.textField.keyboardType = .NumberPad 

      switch indexPath.row { 
      case 0: 
       cell.textField.placeholder = "Card Number" 
       cell.textField.tag = 0 
      case 1: 
       cell.textField.placeholder = "Security Code" 
       cell.textField.tag = 1 
      case 2: 
       cell.textField.placeholder = "Expiration Month" 
       cell.textField.tag = 2 
      case 3: 
       cell.textField.placeholder = "Expiration Year" 
       cell.textField.tag = 3 
      default: 
       break 
      } 
     } else { 
      switch indexPath.row { 
      case 0: 
       cell.textField.placeholder = "First Name" 
       cell.textField.keyboardType = .Default 
       cell.textField.tag = 4 

       if let firstName = sharedUser.userJSON!["firstName"] { 
        cell.textField.text = firstName as? String 
       } 
      case 1: 
       cell.textField.placeholder = "Last Name" 
       cell.textField.keyboardType = .Default 
       cell.textField.tag = 5 

       if let lastName = sharedUser.userJSON!["lastName"] { 
        cell.textField.text = lastName as? String 
       } 
      case 2: 
       cell.textField.placeholder = "Phone Number" 
       cell.textField.keyboardType = .PhonePad 
       cell.textField.tag = 6 
      case 3: 
       cell.textField.placeholder = "Address" 
       cell.textField.keyboardType = .EmailAddress 
       cell.textField.tag = 7 
      case 4: 
       cell.textField.placeholder = "City" 
       cell.textField.keyboardType = .Default 
       cell.textField.tag = 8 
      case 5: 
       cell.textField.placeholder = "State" 
       cell.textField.keyboardType = .Default 
       cell.textField.tag = 9 
      case 6: 
       cell.textField.placeholder = "Zip Code" 
       cell.textField.keyboardType = .NumberPad 
       cell.textField.tag = 10 
      default: 
       break 
      } 
     } 

     return cell 
    } 

我可以做到这一点，但它似乎并不是最好的选择。

func textFieldShouldReturn(textField: UITextField) -> Bool { 
     textField.resignFirstResponder() 

     switch textField.tag { 
     case 0: 
      self.cardNumber = textField.text! 
     case 1: 
      self.securityCode = textField.text! 
     case 2: 
      self.expMonth = textField.text! 
     case 3: 
      self.expYear = textField.text! 
     case 4: 
      self.firstName = textField.text! 
     case 5: 
      self.lastName = textField.text! 
     case 6: 
      self.phoneNumber = textField.text! 
     case 7: 
      self.address = textField.text! 
     case 8: 
      self.city = textField.text! 
     case 9: 
      self.state = textField.text! 
     case 10: 
      self.zipCode = textField.text! 
     default: 
      break 
     } 

     return true 
    } 

Answer 1

您可以简单地创建占位符这样

let placeholders = ["Card Number", "Security Name", ...] 

一个数组，那么你可以使用此代码是不是多余

override func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell { 
     let cell = tableView.dequeueReusableCellWithIdentifier("paymentCell", forIndexPath: indexPath) as! PaymentInfoCell 

    cell.selectionStyle = .None 
    cell.textField.delegate = self 
    let index = indexPath.row + indexPath.section*6 //calculates the index of the text in the array 
    cell.textField.placeholder = placeholders[index] 
    cell.textField.tag = index 

    if indexPath.section == 0 { 
     cell.textField.keyboardType = .NumberPad 
    } else { 
     if indexPath.row == 0 { 
      if let firstName = sharedUser.userJSON!["firstName"] { 
       cell.textField.text = firstName as? String 
      } 
     } else if indexPath.row == 1 { 
      if let lastName = sharedUser.userJSON!["lastName"] { 
       cell.textField.text = lastName as? String 
      } 
     } 
    } 
    return cell 
} 

你可以做同样的你变量，把它们放在一个数组中，只是说

variable[textField.tag] = textField.text!