添加CASE语句的结果

Question

我有以下Oracle SQL查询。给定名称和姓氏后，它会按照任意顺序查找带有一个名称和另一个的首字母的所有记录。我创建了score列，以便将可能的匹配放在结果集的顶部。

SELECT 
    surname, 
    givenname, 
    (CASE WHEN surname = 'Smith' THEN 2 ELSE 0) 
    + (CASE WHEN givenname = 'John' THEN 1 ELSE 0) 
    AS score 
FROM person 
WHERE (surname = 'Smith' AND givenname LIKE 'J%') 
    OR (surname LIKE 'S%' AND givenname = 'John') 
    OR (surname = 'John' AND givenname LIKE 'S%') 
    OR (surname LIKE 'J%' AND givenname = 'Smith') 
ORDER BY 
    score DESC, 
    surname ASC, 
    givenname ASC; 

问题是score是在+的位置给了一个错误。该IDE报告：

Syntax error, expected:
/
*
|

和执行报告：

SQL Error: ORA-00905: missing keyword

我在做什么错？有没有更好的方法来计算分数？

Answer 1

你缺少你的CASE报表END：

SELECT 
    surname, 
    givenname, 
    (CASE WHEN surname = 'Smith' THEN 2 ELSE 0 END) -- < add END 
    + (CASE WHEN givenname = 'John' THEN 1 ELSE 0 END) -- < add END 
    AS score 
FROM person 
WHERE (surname = 'Smith' AND givenname LIKE 'J%') 
    OR (surname LIKE 'S%' AND givenname = 'John') 
    OR (surname = 'John' AND givenname LIKE 'S%') 
    OR (surname LIKE 'J%' AND givenname = 'Smith') 
ORDER BY 
    score DESC, 
    surname ASC, 
    givenname ASC;