1
我正在extjs + Yii中工作。我的客户端功能在yii中设置,服务器端功能在extjs中。在extjs控制器中我编写了代码发送动态生成存储,设置其代理并使用sync()方法存储。如何通过extjs的store.sync()方法捕获数据发送
review:function()
{ var reviewQuestionStore=Ext.create('Balaee.store.qb.QbqnsStore');
proxy=reviewQuestionStore.getProxy();
Ext.apply(proxy.api,{
read:'http://127.0.0.1/s_balaee/Balaee/index.php/QuestionBank/Qbpaper/ReviewQuestionPaper',
create:'http://127.0.0.1/s_balaee/Balaee/index.php/QuestionBank/Qbpaper/ReviewQuestionPaper',
});
Ext.apply(proxy.writer,{
type:'json',
root:'records'
});
Ext.apply(proxy.reader,{
type:'json',
root:'questions'
});
var getdata=this.getLocalvalue();
UserId=getdata.data.userId;
//Using sync method
var check =Ext.create('Balaee.model.qb.QbqnsModel',{
questionPaperNo:Paperno,
userId: UserId,
});
reviewQuestionStore.add(check);
reviewQuestionStore.sync();
}
所以它的工作是正确的。而其发送JSON格式的数据原样
{"records":{"userId":"5","firstName":"abc","middleName":"","lastName":"","languageId":"","primaryEmail":"[email protected]","birthDate":"","password":"","securityQuestionId":"","securityQuestionAnswer":"","isMale":"","creationTime":"","ipAddress":"","confirmationCode":"","userStatusId":"","question":"","id":null}}
现在,我要赶在警予控制器功能这个数据。我曾试图原样
$postData = json_decode(file_get_contents("php://input"), true);
$clientData = $postData['records'];
和访问我使用$ clientData [“的firstName”]字段。但它不是working.So如何捕捉Yii中的数据是通过ExtJS的的商店同步()方法来发送。
感谢名单先生......它的工作原理... – user1722857 2013-03-15 09:32:12
@ user1722857欢迎您 – 2013-03-15 10:36:09