对不起,如果我做得身世愚蠢的,但我不能让这个if语句的工作...IF语句不工作
它所做的是,它会检查某些值从cookie,设置组合框默认值。
通过调试我可以看到所有的cookie变量都是正确的,但是IF语句似乎没有读取值?前两个IF的工作正确,但最后一个 - 如果不起作用。
任何帮助非常感谢,谢谢
function checkBody() {
var cookie1 = readCookie("Text Colour");
textCol = cookie1 ? cookie1 : "#444";
var cookie2 = readCookie("Background Colour");
backCol = cookie2 ? cookie2 : "white";
var cookie3 = readCookie("Link Colour");
linkCol = cookie3 ? cookie3 : "#0424B5";
var cookie4 = readCookie("Heading1 Colour");
heading1Col = cookie4 ? cookie4 : "#0424B5";
var cookie5 = readCookie("Headings Colour");
headingsCol = cookie5 ? cookie5 : "#99975A";
var element = document.getElementById('colours');
if(textCol == cookie1 && backCol == cookie2)
element.value = "#444,white,#0424B5,#0424B5,#99975A";
else if(textCol == cookie1 && backCol == cookie2)
element.value = "black,yellow,black,black,black";
else if(textCol == cookie1 && backCol == cookie2)
element.value = "black,#87CEFA,black,black,black";
bodyStyle(textCol,backCol,linkCol,heading1Col,headingsCol);
}
您的所有3 if语句使用完全相同的比较......('textCol == COOKIE1 && backCol == cookie2') – 2011-06-06 20:51:39
“不工作”? – 2011-06-06 20:52:15
我是一个白痴,我只是看不到,非常感谢。 – Cristian 2011-06-06 20:52:50