嗨我写这个脚本来获取网站的html,但我看到“无效的请求”错误,但是当我创建一个html表单并提交它时,我没有问题,最新的问题是什么?这里是我的PHP代码:通过curl发出帖子请求
<?php
$url = 'http://convert2mp3.net/en/index.php?p=convert';
$fields = array(
'url' => urlencode("www.youtube.com/watch?v=ntSBKPkk4m4"),
'format' => urlencode("3gp")
);
//url-ify the data for the POST
$fields_string="";
foreach($fields as $key=>$value) { $fields_string .= $key.'='.$value.'&'; }
rtrim($fields_string, '&');
//open connection
$ch = curl_init();
//set the url, number of POST vars, POST data
curl_setopt($ch,CURLOPT_URL, $url);
curl_setopt($ch,CURLOPT_AUTOREFERER,true);
curl_setopt($ch,CURLOPT_FOLLOWLOCATION,true);
curl_setopt($ch,CURLOPT_POST, count($fields));
curl_setopt($ch,CURLOPT_POSTFIELDS, $fields_string);
//execute post
$result = curl_exec($ch);
//close connection
curl_close($ch);
?>
我试过,但我有同样的问题:( – user3120600