加载的图片编辑

Question

我应该从一个文件加载一个图像，这个图像应该覆盖80％的图片框，然后在它上面画一些东西......加载没有问题，但试图绘制任何东西滴具有不合适参数的错误（g.FillRectangle ...）。

我堆栈建议发现刷新图片框，但它改变不了什么...
，我不知道如何解决这个问题？

private void button1_Click_1(object sender, EventArgs e) 
{ 
    pictureBox1.Width = (int)(Width * 0.80); 
    pictureBox1.Height = (int)(Height * 0.80); 

    // open file dialog 
    OpenFileDialog open = new OpenFileDialog(); 
    // image filters 
    open.Filter = "Image Files(*.jpg; *.jpeg; *.gif; *.bmp)|*.jpg; *.jpeg; *.gif; *.bmp"; 
    if (open.ShowDialog() == DialogResult.OK) 
    { 
     // display image in picture box 
     pictureBox1.Image = new Bitmap(open.FileName); 
     // image file path 
     // textBox1.Text = open.FileName; 
     g.FillRectangle(Brushes.Red, 0, 0, 20, 50); 
     pictureBox1.Refresh(); 
    } 
} 

Answer 1

使用Graphics.FromImage或Control.CreateGraphics方法上画出你图像：

var img = new Bitmap(open.FileName); 
using (Graphics g = Graphics.FromImage(img)) 
{ 
    g.FillRectangle(Brushes.Red, 0, 0, 20, 50); 
} 
pictureBox1.Image = img; 

或（通过使用Anonymous Methods例如）直接在PictureBox通过Paint事件绘制：

pictureBox1.Paint += (s, e) => e.Graphics.FillRectangle(Brushes.Red, 0, 0, 20, 50); 

Answer 2

下面的代码为我工作的罚款....你可以尝试同样的

private void button1_Click(object sender, EventArgs e) 
     { 
      pictureBox1.Width = (int)(Width * 0.80); 
      pictureBox1.Height = (int)(Height * 0.80); 


      // open file dialog 
      OpenFileDialog open = new OpenFileDialog(); 

      // image filters 
      open.Filter = "Image Files(*.jpg; *.jpeg; *.gif; *.bmp)|*.jpg; *.jpeg; *.gif; *.bmp"; 
      if (open.ShowDialog() == DialogResult.OK) 
      { 
       // display image in picture box 
       pictureBox1.Image = new Bitmap(open.FileName); 
       // image file path 
       // textBox1.Text = open.FileName; 
       Graphics g = Graphics.FromImage(pictureBox1.Image); 
       g.FillRectangle(Brushes.Red, 0, 0, 20, 50); 
       pictureBox1.Refresh(); 
      } 
     }