所以我的新节目,并已被困在这几天... 添加数据我有一个数组,如下所示从plist中从阵列
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE plist PUBLIC "-//Apple//DTD PLIST 1.0//EN" "http://www.apple.com /DTDs/PropertyList-1.0.dtd">
<plist version="1.0">
<array>
<dict>
<key>question</key>
<string>2 + 2 = ?</string>
<key>A</key>
<string>2</string>
<key>B</key>
<string>7</string>
<key>C</key>
<string>3</string>
</dict>
<dict>
<key>question</key>
<string>2 + 3 = ?</string>
<key>A</key>
<string>5</string>
<key>B</key>
<string>2</string>
<key>C</key>
<string>6</string>
</dict>
</array>
</plist>
那么我想这些存储的数组每。然后,我在每个故事板上都有一个标签,并且要将每个键分配给不同的标签,但我似乎做错了。这里是我的代码
- (void)showNextQuestion
{
NSArray *rootArray = [NSArray arrayWithContentsOfFile:[[NSBundle mainBundle] pathForResource:@"question" ofType:@"plist"]];
int numItems = [rootArray count];
currentQuestion = -1;
currentQuestion++;
NSMutableArray *question = [NSMutableArray arrayWithCapacity:numItems];
NSMutableArray *A = [NSMutableArray arrayWithCapacity:numItems];
NSMutableArray *B = [NSMutableArray arrayWithCapacity:numItems];
NSMutableArray *C = [NSMutableArray arrayWithCapacity:numItems];
for (NSDictionary *itemData in rootArray) {
[question addObject:[itemData objectForKey:@"question"]];
[A addObject:[itemData objectForKey:@"A"]];
[B addObject:[itemData objectForKey:@"B"]];
[C addObject:[itemData objectForKey:@"C"]];
self.questionasked.text =question;
self.answer1.text = A;
self.answer2.text = B;
self.answer3.text = C;
}
}
4个标签questionsasked,ANSWER1,ANSWER2,ANSWER3 ......如何正确
您似乎将一个NSMutableArray分配给标签的文本字段。由于您有多个问题,因此您需要指定您想在“self.?????.text =?;'行 – 2013-02-21 21:22:00
嘿david中显示的问题的索引。感谢您的帮助,我想要做的是采取数组中的任何事情,说出问题并将其放在问号标签中......这是否有道理? – Sfocker 2013-02-21 21:26:38
可以理解,但是您只有一组标签和多个问题,并且您正在分配for语句中的标签,因此您也覆盖了分配。你的意思是把问题放在表格视图或其他什么地方,然后在选择问题的按钮中显示可能的答案?你想达到什么目的? – 2013-02-21 21:29:36