如何在php中退出javascript代码

Question

我正致力于将数据发送到ajax。

 $phpArray = array("ok", " 
      <script> 
     mygallery = [ 
         {type: "image", image: "img/gallery/slider/1.jpg", thmb: "img/gallery/slider/thumbs/1.jpg", alt: "", title: "", description: "", titleColor: "#000000", descriptionColor: "#000000"}, 
     {type: "image", image: "img/gallery/slider/2.jpg", thmb: "img/gallery/slider/thumbs/2.jpg", alt: "", title: "", description: "", titleColor: "#000000", descriptionColor: "#000000"}, 
</script>" 
     ); 
    echo json_encode($phpArray); 

如何正确执行此操作？我曾尝试在网上的javascript逃走，但doesn't工作

Answer 1

就难逃“用反斜杠：

$phpArray = array("ok", " 
      <script> 
     mygallery = [ 
         {type: \"image\", image: \"img/gallery/slider/1.jpg\", thmb: \"img/gallery/slider/thumbs/1.jpg\", alt: \"\", title: \"\", description: \"\", titleColor: \"#000000\", descriptionColor: \"#000000\"}, 
     {type: \"image\", image: \"img/gallery/slider/2.jpg\", thmb: \"img/gallery/slider/thumbs/2.jpg\", alt: \"\", title: \"\", description: \"\", titleColor: \"#000000\", descriptionColor: \"#000000\"}, 
</script>" 
); 
echo json_encode($phpArray);