我有两个JTabbedPanes,JTabbedPane1 如何按下JTabbedPane2中的按钮来显示JTabbedPane1?如何通过单击按钮切换jTabbedPane中的选项卡?
这里是JTabbedPane的代码:
public class TabbedPane extends JFrame {
public TabbedPane() {
setTitle("Tabbed Pane");
setSize(300,300);
JTabbedPane jtp = new JTabbedPane();
getContentPane().add(jtp);
JPanel1 jp1 = new JPanel1();//This will create the first tab
JPanel jp2 = new JPanel2();//This will create the second tab
//add panel .........
//example usage
public static void main (String []args){
TabbedPane tab = new TabbedPane();
}
}
这里是类JPane1:对INT
JButton的测试=新的JButton( “新闻”
... JLabel label1 = new JLabel();
label1.setText("This is Tab 1");
jp1.add(label1);
和类Jpane2与按钮); jp2.add(test);
ButtonHandler phandler = new ButtonHandler();
test.addActionListener(phandler);
setVisible(true);
} 这样的问题是在这里按钮的ActionListener在Jpanel2
class ButtonHandler implements ActionListener{
public void actionPerformed(ActionEvent e){
// what i do now ? to call jpanel 1 show ![alt text][1]
}
}
伟大:D我只是忘记了索引。 – gumuruh 2017-12-12 02:10:31