使用python函数调整代码

Question

#Passwordgen 
#Generate a password 

def main(): 

    #Ask the user to input a long string of words, separated by spaces 
    sent = input("Enter a sentance separated by spaces: ") 

    #Ask the user to input a position within each word 
    #Take the position of that word 
    pos = eval(input("Input a position within each word: ")) 
    words = sent.split(" ") 

    wordy = ""         
    #loops through the word to take the position of the letter 
    for word in words: 
     wordy = wordy + word[pos] 

    #Prints out the letters as a password 
    print("Your password is: ", wordy) 


main() 

我的教授希望我输出从零开始，从零开始到包括用户输入的位置在内的每个位置生成的密码。它应该使用密码（短语，位置）函数来生成密码。

使用字符串格式打印每个密码输出行，如下所示。

例如：

Enter words, separated by spaces: correct horse battery staple 
Up to position within each word: 3 

Password 0: chbs 
Password 1: ooat 
Password 2: rrta 
Password 3: rstp 

Answer 1

上的代码干得好，到目前为止，只需要一些调整：

#Passwordgen 
#Generate a password 

def main(): 

    #Ask the user to input a long string of words, separated by spaces 
    sent = input("Enter a sentance separated by spaces: ") 

    #Ask the user to input a position within each word 
    #Take the position of that word 
    pos = int(input("Input a position within each word: ")) 
    words = sent.split(" ") 

    # set a counter variable to count each password generateed 
    count = 0 

    #loops through the word to take the position of the letter 
    for p in range(pos+1): 
     # reset wordy for each new password we are generating 
     wordy = "" 
     for word in words: 
      wordy = wordy + word[p] 
     #Prints out the letters as a password 
     print("Your password {c} is: {pw}".format(c = count, pw = password)) 
     count += 1 

main() 

我们需要跟踪的，我们是从拍摄中的字母位置每个字，这就是for p in range(pos+1)行（我们做pos+1获得位置高达3+1（或4），因为范围上升，但不包括该值。

另外，根据说明，我们需要"Use string formatting to print each of the password output lines"，所以参考这些python3 format examples，我们可以格式化每个密码的输出和相关的计数。

希望这可以帮助你，欢呼！