事情是这样的:
SELECT first_user.id_user, second_user.id_user, COUNT(first_user.id_user) AS total_matches
FROM likes AS first_user
JOIN likes AS second_user
ON second_user.id_artist = first_user.id_artist
AND second_user.id_user != first_user.id_user
GROUP BY first_user.id_user, second_user.id_user
ORDER BY total_matches DESC
LIMIT 1
注意,这不是很有效。解决此问题的一种方法是创建一个包含此查询输出的“缓存表”,并删除LIMIT 1
部分。添加一些相关索引并查询此缓存表。您可以设置一个cron作业来定期更新此表。
实施例:
CREATE TABLE IF NOT EXISTS `likes` (
`id_user` varchar(50) DEFAULT NULL,
`id_artist` varchar(50) DEFAULT NULL
) ENGINE=MyISAM DEFAULT CHARSET=latin1;
INSERT INTO `likes` (`id_user`, `id_artist`) VALUES ('8', '39'), ('8', '37'), ('4', '37'), ('8', '24'), ('8', '7'), ('4', '28'), ('8', '28'), ('4', '27'), ('4', '11'), ('8', '49'), ('4', '7'), ('4', '40'), ('4', '29'), ('8', '22'), ('4', '29'), ('8', '11'), ('8', '28'), ('4', '7'), ('4', '31'), ('8', '42'), ('8', '25'), ('4', '25'), ('4', '17'), ('4', '32'), ('4', '46'), ('4', '19'), ('8', '34'), ('3', '32'), ('4', '21')
+---------+---------+---------------+
| id_user | id_user | total_matches |
+---------+---------+---------------+
| 8 | 4 | 7 |
+---------+---------+---------------+
感谢您的帮助,您的查询就像一个chram :) – MonsieurNinja
@sikko高兴地帮助!与你的项目祝你好运:) –