我在WordPress中有一个AJAX函数,它调用一个PHP函数来返回数据库中的瞬态记录的值。为什么AJAX json脚本返回额外的0(零)
当我使用jQuery调用函数时,我收到结果,但它总是有一个额外的0(零)附加到值。
这里是我的jQuery函数:
(function($) {
$(document).ready(function() {
var AdvancedDashboardWidget = function(element, options)
{
var ele = $(element);
var settings = $.extend({
action: '',
service: '',
countof: '',
query: '',
callback:''
}, options || {});
this.count=0;
var url='';
switch(settings.service)
{
case 'facebook':
if(settings.countof=='likes' || settings.countof=='talks')
{
ajaxCall(action,ele,settings);
}
}
};
var ajaxCall = function(action,ele,settings){
opts = {
url: ajaxurl, // ajaxurl is defined by WordPress and points to /wp-admin/admin-ajax.php
type: 'POST',
async: true,
cache: false,
dataType: 'json',
data:{
action: settings.action // Tell WordPress how to handle this ajax request
},
success:function(response) {
//alert(response);
ele.html(response);
return;
},
error: function(xhr,textStatus,e) { // This can be expanded to provide more information
alert(e);
//alert('There was an error');
return;
}
};
$.ajax(opts);
};
$.fn.advanceddashboardwidget = function(options)
{
return this.each(function()
{
var element = $(this);
// Return early if this element already has a plugin instance
if (element.data('advanceddashboardwidget')) return;
// pass options to plugin constructor
var advanceddashboardwidget = new AdvancedDashboardWidget(this, options);
// Store plugin object in this element's data
element.data('advanceddashboardwidget', advanceddashboardwidget);
});
};
});
})(jQuery);
但是也有参与,这是主要的jQuery的功能与WordPress通信,并返回PHP函数的值更辅助功能。
的问题是,如果该值例如返回为“99
”,它将为“990
”
这里是jQuery是调用PHP函数返回:
/**
* Get Facebook Likes
*/
public function get_facebook_likes(){
echo 99;
}
如果我将以上内容更改为return 99;
,我会收到纯文本0
你添加一个数字时,你应该增加一个数量为数字的字符串,无论是在PHP端或使用Javascript结束? – JayC
只是为了调试我有PHP函数“return 99;”。它仍然返回990 – Jason