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我使用Spring 3.1.1.RELEASE,JUnit 4.8.1和Hibernate 4.1.0.Final。我有这个在我的测试应用程序上下文定义:如何从JUnit测试中的EntityManagerFactory获取属性?
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="packagesToScan" value="org.myco.subco,com.parentco.fdr.myproject" />
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter"/>
</property>
<property name="dataSource" ref="dataSource"/>
<property name="jpaPropertyMap" ref="jpaPropertyMap" />
</bean>
我如何获得“packagesToScan”特性,以我的JUnit测试一个字符串?我试过
@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration({ "classpath:test-context.xml" })
public class SerializableTest extends AbstractNTsubcoTests
{
@Autowired
private EntityManagerFactory m_entityManagerFactory;
@Test
public final void testSerializable()
{
final String packagesToScan = (String) m_entityManagerFactory.getProperties().get("packagesToScan");
System.out.println("packagesToScan:" + packagesToScan);
} // testSerializable
}
但是,尽管事实上我已经在上下文中定义了一个非空值,但上面输出的是“null”。