R文本挖掘 - 文本字段之间的交集

Question

我想知道是否有一种快速方法来查找2个文本字符串之间的定向交集，例如

t1 <- "I have achieved my goals over the past 20 years and look forward for my next chalanges" 
t2 <- " have achieved goals and look my chalanges some other words bla bla" 

t1 isContainedIn t2将返回7，因为在t1中显示的7个单词也在t2中显示。 此外，t1和t2是数据框中的2列，所以我需要将该函数应用于整个数据框，并将结果列附加到我的原始数据框中。 这是“data.selected”我的数据框架的样子：

 keywords           title 
1 Samsung UN48H6350 48" Samsung UN48H6350 48" Full 1080p Smart HDTV 120Hz with Wi-Fi +$50 Visa Gift Card 
2 Samsung UN48H6350 48"  Samsung UN48H6350 48" Full HD Smart LED TV -Bundle- (See Below for Contents) 
3 Samsung UN48H6350 48"  Samsung UN48H6350 48" Class Full HD Smart LED TV -BUNDLE- See below Details 
4 Samsung UN48H6350 48"  Samsung UN48H6350 48" Full HD Smart LED TV With BD-H5100 Blu-ray Disc Player 
5 Samsung UN48H6350 48"     Samsung UN48H6350 48" Smart 1080p Clear Motion Rate 240 LED HDTV 
6 Samsung UN48H6350 48"   Samsung UN48H6350 - 48-Inch Full HD 1080p Smart HDTV 120Hz with Wi-Fi 
7 Samsung UN48H6350 48"    Samsung 6350 Series UN48H6350 48" 1080p HD LED LCD Internet TV NEW 
8 Samsung UN48H6350 48" Samsung Un48h6350af 75" 1080p Led-lcd Tv - 16:9 - Hdtv 1080p - (un75h6350afxza) 
9 Samsung UN48H6350 48"       Samsung UN48H6350 - 48" HD 1080p Smart HDTV 120Hz Bundle 
10 Samsung UN48H6350 48" Samsung UN48H6350 - 48-Inch Full HD 1080p Smart HDTV 120Hz with Wi-Fi, (R#416) 

Answer 1

我想另一个类似的方式将通过只使用一个简单的match

string <- strsplit(c(t1, t2), "\\s+") # similar to @Richard 
length(na.omit(match(string[[2]], string[[1]]))) 
## [1] 7 

或许lapply

length(unlist(lapply(string[[2]], intersect, string[[1]]))) 
## [1] 7 

Answer 2

我不是你的意思是由方向重要十分清楚。除非您更改数据，否则交点的长度不应改变。这可能是你正在寻找的。

length(Reduce(intersect, strsplit(c(t1, t2), "\\s+"))) 
# [1] 7 

如果切换到c(t1, t2)你c(t2, t1)可以看到在Reduce输出的差异。但正如我所说，长度仍然是一样的。这只是组的顺序有所不同。