在排序文件中的数据时遇到问题

Question

我正在打开并读取.txt文件，并试图以0.x或0.xy或0.xyz格式保存值。

x必须是数字1-9

Y不能是0或一个奇数

Z不能是0或偶数

我的当前代码只保存在该变量格式为0.x，但跳过了0.xy和0.xyz。

对于文本文件有16000元，并包含整数，浮点数和字符串：

0.03243234

234.234

0.223

0.2

MWFE

等

list = [] 

with open("exam2data.txt") as f: 
    for line in f: 
     line = f.readline() 
     xCounter = 0 
     yCounter = 0 
     zCounter = 0 

     try: 
      lineFloat = float(line) 
      if lineFloat < 1: 
       if len(line) == 4: 
        if line[3] == 0: 
         pass 
        else: 
         list.append(lineFloat) 
         xCounter += 1 

       elif len(line) == 5: 
        if line[3] == 0: 
         pass 
        else: 
         if line[2] == 0: 
          pass 
         else: 
          y = float(line[4]) 
          if (y % 2 == 0): 
           list.append(lineFloat) 
           yCounter += 1 
          else: 
           pass 

       elif len(line) == 6: 
        if line[4] == 0: 
         pass 
        else: 
         if line[5] == 0: 
          pass 
         else: 
          if line[3] == 0: 
           pass 
          else: 
           y = float(line[4]) 
           z = float(line[5]) 
           if (y % 2 == 0): 
            if (z % 2 == 1): 
             list.append(lineFloat) 
             zCounter += 1 
            else: 
             pass 
           else: 
            pass 


     except: 
      pass 

print(len(list)) 
print(', '.join(map(str, list))) 

Answer 1

我的坏人。在阅读完该行后忘记删除\ n。我添加了strip方法并为此调整了字符串。

line = data.rstrip("\n") 

生成的代码：

list = [] 

with open("exam2data.txt") as f: 
    for data in f: 
     data = f.readline() 
     xCounter = 0 
     yCounter = 0 
     zCounter = 0 
     line = data.rstrip("\n") 
     try: 
      lineFloat = float(line) 
      if lineFloat < 1: 
       if len(line) == 3: 
        if line[2] == 0: 
         pass 
        else: 
         list.append(lineFloat) 
         xCounter += 1 

       elif len(line) == 4: 
        if line[3] == 0: 
         pass 
        else: 
         if line[2] == 0: 
          pass 
         else: 
          y = float(line[3]) 
          if (y % 2 == 0): 
           list.append(lineFloat) 
           yCounter += 1 
          else: 
           pass 

       elif len(line) == 5: 
        if line[4] == 0: 
         pass 
        else: 
         if line[3] == 0: 
          pass 
         else: 
          if line[2] == 0: 
           pass 
          else: 
           y = float(line[3]) 
           z = float(line[4]) 
           if (y % 2 == 0): 
            if (z % 2 == 1): 
             list.append(lineFloat) 
             zCounter += 1 
            else: 
             pass 
           else: 
            pass 


     except: 
      pass 

print(len(list)) 
print(', '.join(map(str, list))) 

Answer 2

你的问题要问更好。例如，当号码没有“z”时会发生什么。 x必须是数字，但文件中有字符串？一些示例输入和预期输出将有所帮助。如果我理解了这个问题，那么下面的内容应该可行我更喜欢用数学来隔离数字，但这是个人偏好。并且请注意，我为等于或小于零的数字添加了一个测试。你永远不能相信文件恕我直言的内容。

def test_xyz(num_in): 
    x, remain_x=divmod(num_in*10, 1) 
    print "test_xyz", num_in, 
    if (1 <= x <= 9): 
     print "good x", x 
    else: 
     print "Bad x" , x 
     return 

    if remain_x > 0: 
     y, remain_y=divmod(remain_x*10, 1) 
     if (y != 0) and (y%2 == 0): 
      print "good y" 
     else: 
      print "Bad y", y 
      return 

     if remain_y > 0: 
      z, remain_z=divmod(remain_y*10, 1) 
      if (z != 0) and (z%2 != 0): 
       print "good z" 
      else: 
       print "Bad z", z 
    return 

##----------------------------------------------------------- 
test_data=""".223 
0.2 
1.234 
0.23456 
0.023 
0.101""" 

recs=test_data.split("\n") 
for rec in recs: 
    rec=float(rec) 
    print "\n number", rec 
    if rec < 1 and rec > 0: 
     test_xyz(rec) 
    else: 
     print "number >= 1" 

Answer 3

这是一种文本匹配方法。我将每个搜索模式分解到它自己的函数中，并引入了一个装饰器来跟踪结果。

每个匹配函数在成功时返回一个字符串，或在失败时返回None。这些功能是相互排斥的（最多可以成功），因此我可以安全地将结果与or（None or "text"给出"text"）合并。

INFILE = "exam2data.txt" 
XS = set("123456789") 
YS = set("2468") 
ZS = set("13579") 

def count_not_none(fn): 
    """ 
    A decorator which counts the number of times the wrapped 
     function returns a value other than None 
    """ 
    def wrapped_fn(s): 
     result = fn(s) 
     if result is not None: 
      wrapped_fn.count += 1 
     return result 
    wrapped_fn.count = 0 
    return wrapped_fn 

@count_not_none 
def match_x(line): 
    if len(line) == 3 and line[:2] == "0." and line[2] in XS: 
     return line 
    else: 
     return None 

@count_not_none 
def match_xy(line): 
    if len(line) == 4 and line[:2] == "0." and line[2] in XS and line[3] in YS: 
     return line 
    else: 
     return None 

@count_not_none 
def match_xyz(line): 
    if len(line) == 5 and line[:2] == "0." and line[2] in XS and line[3] in YS and line[4] in ZS: 
     return line 
    else: 
     return None 

def main(): 
    # search for matching lines 
    matches = [] 
    with open(INFILE) as inf: 
     for line in inf: 
      line = line.strip() 
      result = match_x(line) or match_xy(line) or match_xyz(line) 
      if result is not None: 
       matches.append(line) 
    # report on the results 
    print("Matched 0.x {} times".format(match_x.count)) 
    print("Matched 0.xy {} times".format(match_xy.count)) 
    print("Matched 0.xyz {} times".format(match_xyz.count)) 
    print("{} matches found".format(len(matches))) 
    print(", ".join(matches)) 

if __name__=="__main__": 
    main()