Python嵌套字典循环

Question

是否有更好/更清洁/更短的方式获得相同的输出，如下所示？

import plistlib 
pl = plistlib.readPlist('/Users/username/Documents/wifi1.plist') 

n = len(pl) 
count = 0 
while (count < n): 
    print('----------------') 
    print(pl[count]['NOISE']) 
    print(pl[count]['RSSI']) 
    print(pl[count]['SSID_STR']) 
    print(pl[count]['BSSID']) 
    count += 1 

我曾尝试：

for sub_dict in pl.values(): 
    print(sub_dict['NOISE'], sub_dict['RSSI'], sub_dict['SSID_STR'], sub_dict['BSSID']) 

，但我得到：

Traceback (most recent call last): 
    File "plistread.py", line 17, in <module> 
    for sub_dict in pl.values(): 
AttributeError: 'list' object has no attribute 'values' 

Answer 1

你只需要：

for sub_dict in pl: 

由于pl是一个列表，通过该列表进行迭代会给你每个子d字典反过来。

一个简单的例子：

>>> l = [1,2,3,4] 
>>> for x in l: 
... print x, 
... 
1 2 3 4 

Answer 2

你可以使用一个>>>在< < <声明

for sub_dict in pl: 

http://docs.python.org/tutorial/controlflow.html#for-statements

Answer 3

PL是一个列表，而不是一本字典。

所以，你应该遍历PL由：

for sub_dict in pl: 
    print(sub_dict['NOISE'], sub_dict['RSSI'], sub_dict['SSID_STR'], sub_dict['BSSID']) 

Answer 4

如果我理解正确：

keys = ['NOISE', 'RSSI' ... rest of keys] 
input = [{'NOISE':1, 'RSSI':2 ... rest of data}, {'NOISE':11, 'RSSI':22 ... rest of data} ... rest of data] 

data = [[sub_dict[key] for key in keys] for sub_dict in input]