捕获http错误

Question

例如，如何捕获python和urllib（2）中页面的404和403错误？

有没有快速的方法没有大的类包装？

添加信息（堆栈跟踪）：

Traceback (most recent call last): 
    File "test.py", line 3, in <module> 
    page = urllib2.urlopen("http://localhost:4444") 
    File "/usr/lib/python2.6/urllib2.py", line 126, in urlopen 
    return _opener.open(url, data, timeout) 
    File "/usr/lib/python2.6/urllib2.py", line 391, in open 
    response = self._open(req, data) 
    File "/usr/lib/python2.6/urllib2.py", line 409, in _open 
    '_open', req) 
    File "/usr/lib/python2.6/urllib2.py", line 369, in _call_chain 
    result = func(*args) 
    File "/usr/lib/python2.6/urllib2.py", line 1161, in http_open 
    return self.do_open(httplib.HTTPConnection, req) 
    File "/usr/lib/python2.6/urllib2.py", line 1136, in do_open 
    raise URLError(err) 
urllib2.URLError: <urlopen error [Errno 111] Connection refused> 

Answer 1

import urllib2 
try: 
    page = urllib2.urlopen("some url") 
except urllib2.HTTPError, err: 
    if err.code == 404: 
     print "Page not found!" 
    elif err.code == 403: 
     print "Access denied!" 
    else: 
     print "Something happened! Error code", err.code 
except urllib2.URLError, err: 
    print "Some other error happened:", err.reason 

在你的情况下，错误发生在HTTP连接可以建立之前就已经 - 所以你需要添加映入URLError另一个错误处理程序。但这与404或403错误无关。

Answer 2

req = urllib2.Request('url') 
>>> try: 
>>>  urllib2.urlopen(req) 
>>> except urllib2.URLError, e: 
>>>  print e.code 
>>>  print e.read()