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我想保存切换按钮状态,以便用户不能投票两次。 我有一个消息错误:异常' - [NSDictionaryM长度...在目标AsyncLocalStorage上调用multiSet时引发任何想法?AsyncStorage使用React Native保存状态
this.state= {
trueSwitchIsOn: false,
};
onSwitchChange(_key){
const{trueSwitchIsOn}=this.state;
switch (this.state.trueSwitchIsOn){
case false:
return(
<TouchableHighlight onClick={this.onPressIcon(_key)}>
{this.setState({trueSwitchIsOn: true})}
</TouchableHighlight>
);
case true:
return(
<TouchableHighlight onClick={this.onUnPressIcon(_key)}>
{this.setState({trueSwitchIsOn: false})}
</TouchableHighlight>
);
}
}
onPressIcon(word){
AsyncStorage.setItem('AlreadyLiked', {trueSwitchIsOn});
const{trueSwitchIsOn}=this.state;
this.setState({trueSwitchIsOn : true});
}
onUnPressIcon(word){
AsyncStorage.setItem('NotAlreadyLiked', {trueSwitchIsOn: false});
const{trueSwitchIsOn}=this.state;
this.setState({trueSwitchIsOn : false});
<Switch>
onValueChange={(value)=>this.onSwitchChange(_key)}
</Switch>