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在如下所示的Maven程序集中,结果是发生了递归,重新包括基本目录。如何在Maven程序集的basedir中包含所有文件(不是目录)
继实际上消耗CPU和不返回失败:
<assembly xmlns="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2 http://maven.apache.org/xsd/assembly-1.1.2.xsd">
<id>deploy</id>
<baseDirectory>hive</baseDirectory>
<includeBaseDirectory></includeBaseDirectory>
<formats>
<format>zip</format>
</formats>
<fileSets>
<fileSet>
<directory>${basedir}/lib</directory>
<outputDirectory>lib</outputDirectory>
</fileSet>
<fileSet>
<directory>${basedir}</directory>
<outputDirectory></outputDirectory>
</fileSet>
</fileSets>
<files>
<file>
<source>${basedir}/target/${project.build.finalName}.jar</source>
<outputDirectory>lib</outputDirectory>
</file>
</files>
</assembly>
相反,如果基本目录不遂把/ *已经适当地包括lib下的文件和组装成功。那么......这里的正确语法是什么?谢谢!
继建立输出拉链,但没有在基本目录中的文件 - 所以它是不完整:
<assembly xmlns="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2 http://maven.apache.org/xsd/assembly-1.1.2.xsd">
<id>deploy</id>
<baseDirectory>hive</baseDirectory>
<includeBaseDirectory></includeBaseDirectory>
<formats>
<format>zip</format>
</formats>
<fileSets>
<fileSet>
<directory>${basedir}/lib</directory>
<outputDirectory>lib</outputDirectory>
</fileSet>
</fileSets>
<files>
<file>
<source>${basedir}/target/${project.build.finalName}.jar</source>
<outputDirectory>lib</outputDirectory>
</file>
</files>
</assembly>