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我需要使用PHP XPath &节点从以下代码中获取图像的src值。在document.write中获取img src值PHP
样本HTML
<div class=\"thumb-inside\">
<div class=\"thumb\">
<script>document.write(thumbs.replaceThumbUrl('<a href=\"....."><img src=\".....\" /></a>'));</script>
</div>
</div>
我想是这样的:
$node = $xpath->query("div[@class='thumb-inside']/div[@class='thumb']/a/img/attribute::src", $e);
$th = $node->item(0)->nodeValue;
你已经试过了什么? – BenM
$ node = $ xpath-> query(“div [@ class ='thumb-inside']/div [@ class ='thumb']/a/img/attribute :: src”,$ e); \t \t $ th = $ node-> item(0) - > nodeValue; – romeo
我这样绑定 – romeo