过滤MongoDB中与自己的领域

Question

我想通过自己的领域，具体时间，即过滤MongoDB的文件：

{time1: timeval1, time2: timeval2} 

我希望能够得到一个结果集（像.find （））其中timeval1大于timeval2。

我不知道如何用$ gt做到这一点，并找不到类似的东西。任何想法如何做到这一点？

我在djangi项目中从pymongo访问它......但我想要的只是mongodb查询。

Answer 1

您可以使用$where运算符和一个javascript表达式来编写您的查询逻辑。

http://www.mongodb.org/display/DOCS/Advanced+Queries#AdvancedQueries-JavascriptExpressionsand%7B%7B%24where%7D%7D

> db.newColl.find() 

{ "_id" : ObjectId("4fbdcdd6e79d66d9e681b185"), "time1" : 123, "time2" : 22 } 
{ "_id" : ObjectId("4fbdcddee79d66d9e681b186"), "time1" : 11, "time2" : 220 } 
{ "_id" : ObjectId("4fbdcde6e79d66d9e681b187"), "time1" : 331, "time2" : 2120 } 
{ "_id" : ObjectId("4fbdcdece79d66d9e681b188"), "time1" : 1, "time2" : 20 } 

> db.newColl.find({'$where' : 'this.time1 > this.time2' }); 

{ "_id" : ObjectId("4fbdcdd6e79d66d9e681b185"), "time1" : 123, "time2" : 22 } 


> db.newColl.find({'$where' : 'this.time1 < this.time2' }); 

{ "_id" : ObjectId("4fbdcddee79d66d9e681b186"), "time1" : 11, "time2" : 220 } 
{ "_id" : ObjectId("4fbdcde6e79d66d9e681b187"), "time1" : 331, "time2" : 2120 } 
{ "_id" : ObjectId("4fbdcdece79d66d9e681b188"), "time1" : 1, "time2" : 20 }