我想在它的字符串中显示下面的值。字符串到数组
标准==============(
"Communication skills",
"Open to following directions",
"Prepared for your case",
"Ability to obtain resolution",
"Willingness to work the process"
)
标准是从Web服务
我想在它的字符串中显示下面的值。字符串到数组
标准==============(
"Communication skills",
"Open to following directions",
"Prepared for your case",
"Ability to obtain resolution",
"Willingness to work the process"
)
标准是从Web服务
尝试使用SBJson库来解析JSON响应
#import "SBJson.h"
NSString * criteria = @"Criteria:("Communication skills","Open to following directions","Prepared for your case","Ability to obtain resolution","Willingness to work the process")";
//criteria is your json response or whatever else is your response.
SBJsonParser *jsonParser = [SBJsonParser new];
NSDictionary *jsonData = (NSDictionary *) [jsonParser objectWithString:criteria error:nil];
NSArray *criteriaAry = [[NSArray alloc]init];
criteriaAry= [jsonData objectForKey:@"Criteria"];
来尝试这样,如果字符串值您的字符串是
criteria=(
"Communication skills",
"Open to following directions",
"Prepared for your case",
"Ability to obtain resolution",
"Willingness to work the process"
)
then try like this,
criteria=[criteria stringByReplacingOccurrencesOfString:@"\"" withString:@""];
NSArray *resultArray=[criteria componentsSeparatedByString:@","];//String to Atrray
@Verma:检查第二行。 – Balu
,如果你想转换阵列串试试这个代码
NSArray *st=[yourstring componentsSeparatedByString:@","];
从字符串添加在“”项目到数组使用
NSString *str = @" 'Communication skills','Willingness to work the process'";
NSArray * arr = [str componentsSeparatedByString:@","];
NSLog(@"%@",arr);
u能请详细说明你的问题稍微弥补理解更好地为他人回答你的问题。 –
我只想在视图上显示这些标准值... – Verma
哪些视图...? – Balu