int没有len错误请帮助我吗？

Question

我的程序出了问题，真的很烦我我一直在收到一个错误，我甚至不知道为什么你可以帮我吗？

我不断收到builtins.TypeError：类型“诠释”的对象没有LEN（）错误

当它到达密码verfication阶段，我无法弄清楚的问题是什么..

#Program asking for a username, password and security pin 
#Written by Cole Johnston 
#19/08/13 - 

#Declare/Initialize variables 
sFirstName = "" #User's input of their first name (the minimum is 2 characters) (string) 
sLastName = "" #User's input of their last name (the minimum is 4 characters) (string) 
sPassword = "" #User's input of their password (it must have a minimum length of 6 characters and a maximum length of 10 characters. It must contain at least 2 numbers in the password, it is case sensitive) 
iPinNo = 0 #User's chosen input of security pin (It must be 4 characters long and contain only numbers which are single digit and range between 0-9) 
iCount = 0 #The amount of times the user enters an invalid username (integer) 
sMessage = "" #Message for user (string) 
iFirstNameCheck=0 #Checks first name 
iLastNameCheck=0 #Checks last name 
iPasswordCheck=0 #Checks password 
iPinNoCheck=0 #Checks pin 
sUserName = "" #Creates a username for the user (uses first and last name) 
sPasswordVerification = "" #Checks the password is correct and same as the first one 

def APFirstERROR(): 
    print(("ERROR: Incorrect Attemps consisting of 3 \n\t Closing program")) 
    sys.ext 


def APSecondERROR(): 
    print (("ERROR: Incorrect Attemps consisting of 3 \n\t Closing program")) 
    sys.ext 

def APThirdERROR(): 
    print (("ERROR: Incorrect Attemps consisting of 3 \n\t Closing program")) 
    sys.ext 

def APFourthERROR(): 
    print (("ERROR: Incorrect Attemps consisting of 3 \n\t Closing program")) 
    sys.ext 


#Ask for the users First name 

while len(sFirstName) <2: 
    sFirstName=input("Could you please enter your first name: ") 
    if len(sFirstName) <2: 
     print("\tERROR: I'm sorry, you must enter a minumum of two characters") 
     FirstName = "" 
     iFirstNameCheck = iFirstNameCheck +1 
     print (iFirstNameCheck, "Incorrect attempt") 
     if iFirstNameCheck == 3: 
      APFirstERROR() 

#Ask for the users Last name   
while len(sLastName) <4: 
    sLastName = input("Could you please enter your last name: ") 
    if len(sLastName) <4 : 
     print ("\tERROR: I'm sorry, you must enter a minumum of four characters") 
     LastName = "" 
     iLastNameCheck = iLastNameCheck +1 
     print (iLastNameCheck, "Incorrect attempt") 
     if iLastNameCheck==3: 
      APSecondERROR()  

sUsername = "Congratulations, your username will be " + sLastName[0:4] + sFirstName[0:1] 
print (sUsername)    


while sPassword is "": 
    sPassword=input("Could you please enter a password: ") 
    if len(sPassword) <6 or len(sPassword) >10 : 
     print("ERROR: I'm sorry, your password must be 6 characters or more but not exceeding 10 characters.\nPlease try again") 
     if sum(c.isdigit() for c in sPassword) <2: 
      print("Im sorry, your password does not contain enough numbers.\nThe requirements are a minimum of 2 numbers")   
      sPassword="" 
      iPasswordCheck=iPasswordCheck+1 
      print(iPasswordCheck, "Incorrect Attempt") 
      if iPasswordCheck ==3: 
       sPassword="Incorrect" 
       APErrorThird()    
       break 

#Verify the password 
while sPasswordVerification is "": 
    sPasswordVerification=input("Please enter your password a second time for verification: ") 
    if sPasswordVerification==sPassword: 
     print("That password is Accepted") 
     if not sPasswordVerification==sPassword: 
      sPasswordVerification="" 
      print ("I'm sorry, that password is: Not accepted") 

       a 
#ASk user for pin creation 
while len(iPinNo) <4: 
    iPinNo= input("Now could you please create a pin number. The requirements are that it must be only numbers (0-9). Must be 4 numbers long\n\tpin=?\t\n:") 
    if not re.match("^[1-9]*$", iPinNo): 
     print ("ERROR: I'm sorry but only numbers between 1-9 are allowed!") 
     if len (iPinNo) <4: 
      print ("I'm sorry, your pin number MUST be 4 characters.") 
      iPinNoCheck=iPinNoCheck+1 
      print (iPinNoCheck, "Incorrect Attempt") 
      if iPinNoCheck==3: 
       iPinNo ="Incorrect" 
       APErrorFourth()     

#Display the Username, the Password and the Pin number 

print ("Okay, " + (sFirstName) +" Your username is: ",sUsername) 
print("And, Your password is: ",sPassword) 
print ("Finally , Your Security pin is: ",iPinNo)  

Answer 1

这里：while len(iPinNo) < 4:

iPinNo是一个整数，你不应该来调用整数len()（因此错误）：传递给len()的对象必须是一个序列或映射。

首先将它转换为字符串，使用str()，然后调用len()来获取数字量。

Answer 2

有没有LEN（）方法用于int，LEN（）是用于序列

http://docs.python.org/2/library/functions.html#len

定义： 返回一个对象的长度（项目数）。参数可以是一个序列（字符串，元组或列表）或映射（字典）。

Answer 3

那么，粘贴实际的回溯是非常有用的，这样我们就可以看到堆栈中的哪个位置（以及代码的哪一行）引发异常。

无论如何，在你的代码中，你需要多次询问整数的长度。例如

while len(iPinNo) < 4: 

int类型没有长度。如果你想确保数为4个位数，你可以做

while len(str(iPinNo)) < 4: 

或

while 999 < iPinNo < 10000: 

Answer 4

要得到的十进制数的位数，使用（基数为10）对数。

from math import log10, ceil 
ceil(log10(iPinNo)) 

0的对数是未定义的，所以你必须在测试长度之前检查一下。

---

无论如何，为什么不仅仅是针对10的匹配能力进行测试呢？

while iPinNo < 10000: 

或

while iPinNo < 10**5