如何打印对象列表中的所有搜索匹配

Question

此搜索功能有效，但如果我搜索名为Sarah的动物，并且列表中有两个名为Sarah的动物，它只打印其中的一个。我应该如何使它打印所有的搜索匹配？

def search(): 
choice = int(input(""" 
1 Name 
2 Age 
3 Specie 
4 Gender 
What do yo want to search for? """)) 

if choice == 1: 
    your_search = input("Write the animal name: ").capitalize() 
    for Animals in animal_list: 
     if your_search == Animals.name: 
      print(Animals) 
      break 

    else: 
      print("Sorry, couldn't find any animal called " + your_search + ", maybe check the spelling.") 

Answer 1

尝试

Answer 2

你告诉程序停止搜索找到一个结果后，每个成功匹配后，除去休息。只是删除break命令，并添加标记，如果一个名字，发现他表示：

def search(): 
    choice = int(input(""" 
    1 Name 
    2 Age 
    3 Specie 
    4 Gender 
    What do yo want to search for? """)) 

    if choice == 1: 
     your_search = input("Write the animal name: ").capitalize() 
     found = False 
     for Animals in animal_list: 
      if your_search == Animals.name: 
       found = True 
       print(Animals) 
     if found == False: 
      print("Sorry, couldn't find any animal called " + 
        your_search + ", maybe check the spelling.")