我用这example多个选择下拉列表的创建表列标题从下拉的选择值下拉列表
的index.php
<!DOCTYPE html>
<html>
<head>
<title>Webslesson Tutorial | How to Use Bootstrap Select Plugin with PHP JQuery</title>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.0/jquery.min.js"></script>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" />
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"></script>
<link rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/bootstrap-select/1.12.2/css/bootstrap-select.min.css">
<script src="https://cdnjs.cloudflare.com/ajax/libs/bootstrap-select/1.12.2/js/bootstrap-select.min.js"></script>
</head>
<body>
<br /><br />
<div class="container">
<br />
<h2 align="center">How to Use Bootstrap Select Plugin with PHP JQuery</h2>
<br />
<div class="col-md-4" style="margin-left:200px;">
<form method="post" id="multiple_select_form">
<select name="framework" id="framework" class="form-control selectpicker" data-live-search="true" multiple>
<option value="Laravel">Laravel</option>
<option value="Symfony">Symfony</option>
<option value="Codeigniter">Codeigniter</option>
<option value="CakePHP">CakePHP</option>
<option value="Zend">Zend</option>
<option value="Yii">Yii</option>
<option value="Slim">Slim</option>
</select>
<br /><br />
<input type="hidden" name="hidden_framework" id="hidden_framework" />
<input type="submit" name="submit" class="btn btn-info" value="Submit" />
</form>
<br />
</div>
</div>
</body>
</html>
<script>
$(document).ready(function(){
$('.selectpicker').selectpicker();
$('#framework').change(function(){
$('#hidden_framework').val($('#framework').val());
});
$('#multiple_select_form').on('submit', function(event){
event.preventDefault();
if($('#framework').val() != '')
{
var form_data = $(this).serialize();
$.ajax({
url:"insert.php",
method:"POST",
data:form_data,
success:function(data)
{
//console.log(data);
$('#hidden_framework').val('');
$('.selectpicker').selectpicker('val', '');
alert(data);
}
})
}
else
{
alert("Please select framework");
return false;
}
});
});
</script>
它工作正常,但我想调整根据我的需要在页面上提到的代码。我想创建一个动态表列的名字是我从下拉列表中
选择手动创建表,并在这里给列的名称作为我的代码,这样反而
<?php
ini_set('display_errors', 1);
ini_set('display_startup_errors', 1);
error_reporting(E_ALL);
$ser="10.90.294.23";
$db="Framework";
$user="test";
$pass="test0";
$query = 'SELECT Laravel, Symfony, Codeigniter, CakePHP FROM Framework.list';
$dbDB = new PDO("odbc:Driver=ODBC Driver 13 for SQL Server;Server=10.90.294.23,1456;Database=Framework;Port=1456", $user, $pass);
?>
<!DOCTYPE html>
<html>
<head>
<title>HTML table using Jquery with PHP</title>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.0/jquery.min.js"></script>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" />
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/js/bootstrap.min.js"></script>
</head>
<body>
<br />
<div class="container" style="width:700px;">
<h3 class="text-center">HTML table using Jquery with PHP</h3><br />
<div class="table-responsive" id="employee_table">
<table class="table table-bordered">
<tr>
<th width="10%">Laravel</th>
<th width="30%">Symfony</th>
<th width="10%">Codeigniter</th>
<th width="50%">CakePHP</th>
</tr>
<?php
foreach ($dbDB->query($query) as $row) {
?>
<tr>
<td><?php echo $row['Laravel']; ?></td>
<td><?php echo $row['Symfony']; ?></td>
<td><?php echo $row['Codeigniter']; ?></td>
<td><?php echo $row['CakePHP']; ?></td>
</tr>
<?php
}
?>
</table>
</div>
</div>
<br />
</body>
</html>
我想要的列标题将从选定的值自动创建。 我正在考虑将所选值存储在变量中,例如:Laravel,CakePHP,Yii,Slim然后我根据逗号之间的每个文本创建标题,“
任何人都可以帮忙吗?我尝试过很多方法,但仍然无法实现。谢谢。
全部取决于您如何存储数据以及该$查询变量是什么。 如果您可以向我们显示查询和数据库中的行/列,那么我相信我们可以提供帮助 –
除非您使用相同的示例?如果是这样的话,请将该例添加到问题中,然后再删除该示例。 –
@RichardHousham感谢您的评论我已经添加了我的php文件的所有代码 – JuniorDev