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的BBC RSS提要具有图像在一个特殊的标签:PHP simplpie BBC饲料图像
<media:content>
<media:thumbnail url="http://ichef.bbci.co.uk/wsimagechef/ic/106x60/ats/worldservice/assets/images/2014/07/09/140709111605_gaza_144x81_reuters_nocredit.jpg" width="106" height="60">
<img alt="" width="106" height="60" src="http://ichef.bbci.co.uk/wsimagechef/ic/106x60/ats/worldservice/assets/images/2014/07/09/140709111605_gaza_144x81_reuters_nocredit.jpg"/>
</media:thumbnail>
<media:thumbnail url="http://wscdn.bbc.co.uk/worldservice/assets/images/2014/07/09/140709111605_gaza_144x81_reuters_nocredit.jpg" width="144" height="81">
<img alt="" width="144" height="81" src="http://wscdn.bbc.co.uk/worldservice/assets/images/2014/07/09/140709111605_gaza_144x81_reuters_nocredit.jpg"/>
</media:thumbnail>
</media:content>
我不知道如何访问图像src中的Feed中的我想:
$t = $feed->get_items();
print_r($t[2]->get_item_tags("http://search.yahoo.com/mrss","XXXX"));
其中XXXX我试过内容,IMG媒体,缩略图,媒体:缩略图,但print_r的不给任何输出。这种饲料link
我使用最新版本的了SimplePie 1.3.1