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即时编程相当新颖,我希望我可以准确地描述我的问题。 我想监视输入我的键盘,但我得到这个TypeError:on_press()缺少1所需的位置参数:'钥匙'。TypeError:on_press()缺少1个必需的位置参数:'key'
当我单独实现该功能时,它工作正常。
from pynput import keyboard
def on_press(key):
keys=[]
try: k = key.char # single-char keys
except: k = key.name # other keys
#if key == keyboard.Key.esc: return False # stop listener
if k in ['down', 'left', 'right',"up"]: # keys interested
# self.keys.append(k) # store it in global-like variable
#print('Key pressed: ' + k)
keys.append(k)
return keys
lis = keyboard.Listener(on_press=on_press)
lis.start() # start to listen on a separate thread
lis.join() # no this if main thread is polling self.keys
...但是,如果我从主
pressed_key = on_press()
调用该函数出现以下错误:
File "<ipython-input-7-c3f93c434982>", line 80, in main
pressed_key = on_press()
TypeError: on_press() missing 1 required positional argument: 'key'
请让我知道如果你有任何想法!
错误消息告诉你缺少一个参数。 'on_press()'函数采用被按下的键,而你没有通过该键。 – kindall
请正确缩进您的代码 – jacoblaw