多文件处理

Question

我试图从每个文件中获取信息并使用它来创建一个新文件。每个文件都有一行由一系列数字组成。我希望一个文件的每一行与另一个文件的每一行对齐，然后将每个数字放在一个文件的一行中，以便与另一个文件中另一行的相同位置中的另一个数字相遇。文件'Volume.txt'的每行都移动了一个点（因此代码的k = j + 1）。

* 操作完成后，我不断收到一个重复的汉字。那么我哪里错了？非常感谢！ *

下面是代码：

e = open('C:/Users/MC/Desktop/EODP.txt', 'r') 
v = open('C:/Users/MC/Desktop/Z/Volume.txt', 'r') 
n = open('C:/Users/MC/Desktop/vovere.txt', 'w') 

m = 0 #Used later for letting me know that the first line in the new file completed 

for i in range(0, 3256): # there are 3257 lines per the two files EOPD and Volume 
    l = []    # create a list to put data in during operation 
    er = e.readline()  # 
    es = er.split(', ') # create a list the data from that line of file 
    vr = v.readline()  # 
    vs = vr.split(', ') # same 
    for j in range(len(es)): 
     k = j + 1   # file Volume is shifted one point ahead 
     try: 
      if float(vs[k]) == 0.0: 
       vovere = 0.0    # vovere is the name of the output for each point 
      elif vs[k] == '' or vs[k] == ' ': 
       vovere = 0.0 
      else: 
       vovere = float(es[j])/float(vs[k]) 
     except ValueError:   #kept getting this error: some points weren't numbers 
      vovere = 0.0  
     except IndexError:   # Each file didn't always exactly equal in line length 
      vovere = 0.0 
     la = l.append(float(vovere)) #Creates the list for each new line in new file 
    ls = str(la) 
    l1 = ls.replace('[', '') # Taking away extra notations so the new file is a little 
    l2 = l1.replace(']', '') # more clean and can be put into other programs 
    n.write(l2) 
    if m == 0:     # From here on out is just for me, not necessary** 
     print("The first line is done!") 
     m += 1 
    else: 
     pass 

e.close()      #** Except these of course 
print(e.closed) 
print("Yes, EOPD.txt is closed") 
v.close() 
print(v.closed) 
print("Yes, Volume.txt is closed") 
n.close() 
print(n.closed) 
print("Yes, vovere.txt is now ready for further manipulation!!") 

Answer 1

如果我明白问题的正确这应该做的伎俩：

from itertools import zip_longest # If this was python 2.x import izip_longest instead 

if __name__ == '__main__': 
    input1_lines = [] 
    input2_lines = [] 

    # Read all the input from first file 
    with open('./input1.txt', 'r') as input1: 
     input1_lines = input1.readlines() 

    # Read all the input from first file 
    with open('./input2.txt', 'r') as input2: 
     input2_lines = input2.readlines() 

    # Go through all the lines 
    output_lines = [] 
    for line_number_index in range(len(input1_lines)): 
    # For each line in each input file make a list of items and remove line breaks 
     line1_items = str(input1_lines[line_number_index]).replace('\n', '').split(', ') 
     line2_items = str(input2_lines[line_number_index]).replace('\n', '').split(', ')[1:] 

     # Go through the item lists and merge them, fill empty spots with fillvalue if there are more items in one of the lists 
     this_output_line = [] 
     for zip_entry in zip_longest(line1_items, line2_items, fillvalue='FILL_VALUE'): 
      this_output_line.append(', '.join(zip_entry)) 
     output_lines.append(', '.join(this_output_line)) 

    # Write out the file 
    with open('./output.txt', 'w') as output_file: 
     for line in output_lines: 
      output_file.write('%s\n' % line) 

更换FILL_VALUE，不管你要插入如果有更多的在合并它们时另一个行中的项目。

如果你需要的第一个项目是从input2.txt而不是input1.txt，开关line1_items和line2_items各地for zip_entry in zip_longest(line1_items, line2_items, fillvalue='FILL_VALUE'):

输入2是一个地方的每一行的第一个项目将被忽略。

本我的测试数据：

input1.txt：

0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 
2, 22, 222, 2222 

input2.txt：

z, a, b, c, d, e, f, g, h, i, j, k 
z, a, aaa, aaaa 

结果：

0, a, 1, b, 2, c, 3, d, 4, e, 5, f, 6, g, 7, h, 8, i, 9, j, 10, k 
2, a, 22, aaa, 222, aaaa, 2222, FILL_VALUE