FileInfo的：使FileInfo的参数方法

Question

我有以下VB函数，它接受一个FileInfo对象作为参数：

Public Shared Shadows Sub Start(ByVal filePath As FieldInfo) 
XmlConfigurator.ConfigureAndWatch(New System.IO.FileInfo(filePath.ToString())) 

End Sub 

在另一类我有下面的代码调用该“开始”方法。但是VisStudio指出我传递的'FilePath'参数存在问题。提前致谢！

'Initialize FileInfo object to pass to Start method 
     Dim path As String =    Dim filePath As FileInfo = New FileInfo(path) 

     LoggingManager.Start(**FilePath**) 

Answer 1

看起来你误宣布启动功能，它应该是没有的FileInfo字段信息

Public Shared Shadows Sub Start(ByVal filePath As FileInfo) 
    XmlConfigurator.ConfigureAndWatch(filePath) 
End Sub