因为Hibernate不支持它,你需要实现如图this例如,用户类型。
import org.hibernate.HibernateException;
import org.hibernate.engine.spi.SessionImplementor;
import org.hibernate.type.StandardBasicTypes;
import org.hibernate.usertype.EnhancedUserType;
import java.io.Serializable;
import java.sql.PreparedStatement;
import java.sql.ResultSet;
import java.sql.SQLException;
import java.sql.Types;
import java.time.Instant;
import java.time.LocalDateTime;
import java.time.ZoneId;
import java.util.Date;
public class LocalDateTimeUserType implements EnhancedUserType, Serializable {
private static final int[] SQL_TYPES = new int[]{Types.TIMESTAMP};
@Override
public int[] sqlTypes() {
return SQL_TYPES;
}
@Override
public Class returnedClass() {
return LocalDateTime.class;
}
@Override
public boolean equals(Object x, Object y) throws HibernateException {
if (x == y) {
return true;
}
if (x == null || y == null) {
return false;
}
LocalDateTime dtx = (LocalDateTime) x;
LocalDateTime dty = (LocalDateTime) y;
return dtx.equals(dty);
}
@Override
public int hashCode(Object object) throws HibernateException {
return object.hashCode();
}
@Override
public Object nullSafeGet(ResultSet resultSet, String[] names, SessionImplementor session, Object owner)
throws HibernateException, SQLException {
Object timestamp = StandardBasicTypes.TIMESTAMP.nullSafeGet(resultSet, names, session, owner);
if (timestamp == null) {
return null;
}
Date ts = (Date) timestamp;
Instant instant = Instant.ofEpochMilli(ts.getTime());
return LocalDateTime.ofInstant(instant, ZoneId.systemDefault());
}
@Override
public void nullSafeSet(PreparedStatement preparedStatement, Object value, int index, SessionImplementor session)
throws HibernateException, SQLException {
if (value == null) {
StandardBasicTypes.TIMESTAMP.nullSafeSet(preparedStatement, null, index, session);
} else {
LocalDateTime ldt = ((LocalDateTime) value);
Instant instant = ldt.atZone(ZoneId.systemDefault()).toInstant();
Date timestamp = Date.from(instant);
StandardBasicTypes.TIMESTAMP.nullSafeSet(preparedStatement, timestamp, index, session);
}
}
@Override
public Object deepCopy(Object value) throws HibernateException {
return value;
}
@Override
public boolean isMutable() {
return false;
}
@Override
public Serializable disassemble(Object value) throws HibernateException {
return (Serializable) value;
}
@Override
public Object assemble(Serializable cached, Object value) throws HibernateException {
return cached;
}
@Override
public Object replace(Object original, Object target, Object owner) throws HibernateException {
return original;
}
@Override
public String objectToSQLString(Object object) {
throw new UnsupportedOperationException();
}
@Override
public String toXMLString(Object object) {
return object.toString();
}
@Override
public Object fromXMLString(String string) {
return LocalDateTime.parse(string);
}
}
新的usertype然后可以用@Type注释映射。对于例如
@Type(type="com.hibernate.samples.type.LocalDateTimeUserType")
@Column(name = "invalidate_token_date")
private LocalDateTime invalidateTokenDate;
@Type注释需要实现userType接口的类的完整路径;这是生成映射列的目标类型的工厂。
Here's如何做同样的事情在JPA2.1
而我应该如何改变映射后添加你的答案? – gstackoverflow
更新了使用信息的答案 –
请注意,如果将其转换为存储'java.util.LocalDate'字段,则不能通过'java.sql.Date.toInstant()'方法去执行,因为会抛出异常;使用'toLocalDate'来代替。 – Gwaptiva