的mysql_query返回错误的结果

考虑下面的代码的mysql_query返回错误的结果

if (isset($_SESSION['FBID']) ) { 
    $uid  = $_SESSION['FBID']; 
    $sql  = "SELECT *, count(member_nr) AS notifyMe 
       FROM poolWinners 
       WHERE member_nr = '$uid' AND notification ='1'"; 
    $result = mysql_query($sql); 
    while($row=mysql_fetch_array($result)){ 
     $notification = $row['notifyMe']; 
    }//while 
     if ($notification > 0) { 
     echo '<span class="badge">' . $notification . '</span>'; 
    } //if 
    var_dump($notification); 
} //isset($_SESSION['FBID'])

以上脚本返回成员有多少条信息有，你可以在图像下方 enter image description here

我的问题

的看脚本返回错误的结果（错误的通知数量）。看看下面的表格，会员号码在表格中出现3次如此： $notification = $row['notifyMe']应= 3而不是1

我在这里丢失或做错了什么？感谢您阅读

来源

2015-06-27 Timothy Coetzee

总结的通知列中的值？因为他们看起来每个都是1，就像这样'select sumNot from poolWinners where member_nr ='$ uid'AND notification = 1;'不需要遍历结果，直接得到总和 –

或者执行select count（member_nr） from poolWinners where member_nr ='$ uid'and notification = 1;'并且使用计数而不是总和，以避免大于1的通知值。再次直接取满值，不需要循环结果集 –

使用

$sql  = "SELECT *, count(*) AS notifyMe 
      FROM poolWinners 
      WHERE member_nr = '$uid' AND notification ='1'";

通知count(*)时，将取回多条记录是如何匹配标准。

并在开始时初始化$notification = 0;。

来源

2015-06-27 04:53:59

谢谢生病让它去并让你知道 –

感谢队友，但即时得到同样的问题 –

它仍然返回一（1）....怪异 –

，你是否尝试从这个角度

$sql = "SELECT * FROM poolWinners WHERE member_nr = '$uid' AND notification ='1'"; 

$result = mysql_query($sql); 
$notification = array(); 
    while($row=mysql_fetch_array($result)){ 
     $notification[] = $row['notifyMe']; 
    } 
//an array count on notification should give you the number of elements in the array i.e those that matched the query 

$total_count = count($notification);

来源

2015-06-27 05:20:49 danidee

如果你正在处理少量的行，你可以尝试mysql_num_rows查看返回的行数 – danidee

在代码中接近它的通知将永远之一，因为它会在结果集中只有最后一排的notifyMe领域。

如果你想获得通知的数量，试试这个

if (isset($_SESSION['FBID']) ) { 
    $uid  = $_SESSION['FBID']; 
    $sql  = "SELECT *, count(member_nr) AS notifyMe 
       FROM poolWinners 
       WHERE member_nr = '$uid' AND notification ='1'"; 
    $result = mysql_query($sql); 
    $notification = 0; 
    while($row=mysql_fetch_array($result)){ 
     $notification++; 
     /* 
     OR $notification += $row['notifyMe']; 
     */ 
    }//while 
     if ($notification > 0) { 
     echo '<span class="badge">' . $notification . '</span>'; 
    } //if 
    var_dump($notification); 
} //isset($_SESSION['FBID'])

来源

2015-06-27 05:34:24

$sql  = "SELECT * 
      FROM poolWinners 
      WHERE member_nr = '$uid' AND notification ='1'"; 

$result = mysql_query($sql); 
$notification = mysql_num_rows($result);

来源

2015-06-27 05:45:15 Amir

$sql = "SELECT * FROM poolWinners WHERE member_nr = '$uid' AND notification ='1'"; 

if ($result=mysqli_query($con,$sql)) 
    { 
    // Return the number of rows in result set 
echo "Toal notification".mysqli_num_rows($result); 
    } 

mysqli_close($con); 
?>

来源

2015-06-27 05:46:55

的mysql_query返回错误的结果

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