定位WebView

Question

我有一个表面（它扩展了SurfaceView），一个AdView，现在我想添加一个WebView，我将需要动态定位。

首先，我试图在中心添加我的web视图，并将其大小设置为设备的宽度和高度的一半。我使用的是800X480设备和横向模式，所以现在我想在左侧= 0，顶部= 120，右侧= 800，底部= 360处将边框设置为仅用于测试。后来我就希望能够动态地设置它，但到目前为止，这甚至不工作：

private MySurface surface; 
private AdView adView; 
private WebView 

. 
. 
. 

// create the ad view 
adView = new AdView(this, AdSize.SMART_BANNER, AD_MOB_ID); 
adView.setAdListener(new MyAdListener()); 

// create the surface 
surface = MySurface.getRef(this); 

// set a listener for touch event 
surface.setOnTouchListener(this); 

// create the web view 

webView = new WebView(this); 
webView.setWebViewClient(new WebViewClient()); 
webView.setVisibility(View.GONE); 
LayoutParams webViewParams = new LayoutParams(800,240); // this works 
webViewParams.setMargins(0, 120, 800, 360);    // this does nothing... 

// create a relative layout 
RelativeLayout l = new RelativeLayout(this); 

// add the surface 
l.addView(surface); 

// add the ad view at the bottom 
AdView.LayoutParams adViewParams = new AdView.LayoutParams(
AdView.LayoutParams.WRAP_CONTENT, 
AdView.LayoutParams.WRAP_CONTENT); 

adViewParams.addRule(AdView.ALIGN_PARENT_BOTTOM); 

l.addView(adView, adViewParams); 

l.addView(webView, webViewParams); 

setContentView(l); 

// load an ad 
//loadAdMob(); 

当我后来设置的WebView能见度可见：

webView.loadUrl(url); 
webView.setVisibility(View.VISIBLE); 

看样子正确的宽度和高度，但在开始屏幕:(

谁能帮助的最顶端感谢

Answer 1

好吧，我想我明白了：？

webView = new WebView(this); 
webView.setWebViewClient(new WebViewClient()); 
RelativeLayout.LayoutParams webViewParams= new RelativeLayout.LayoutParams(800, 240); 
webViewParams.addRule(RelativeLayout.CENTER_IN_PARENT); 

RelativeLayout l = new RelativeLayout(this); 
l.addView(surface); 
l.addView(adView, adViewParams); 
l.addView(webView, webViewParams); 
setContentView(l); 

归功于here