那么你只需要改变你的比较功能,包括其他领域类似这样的
Collections.sort(contacts, (Contact c1, Contact c2) -> {
int firstNameComparisonResult = c1.getFirstName().compareTo(c2.getFirstName());
if (firstNameComparisonResult != 0) {
return firstNameComparisonResult;
} else {
return c1.getLastName().compareTo(c2.getLastName());
}
});
警告:这是假定有没有空。
全部的代码,我使用的,如果你想看看:
class Contact{
final String firstName;
final String lastName;
final int age;
public String getFirstName() {
return firstName;
}
public String getLastName() {
return lastName;
}
public int getAge() {
return age;
}
public Contact(String firstName, String lastName, int age) {
this.firstName = firstName;
this.lastName = lastName;
this.age = age;
}
@Override
public String toString() {
return "Contact{" +
"firstName='" + firstName + '\'' +
", lastName='" + lastName + '\'' +
", age=" + age +
'}';
}
}
@Test
public void sortTest(){
List<Contact> contacts = new ArrayList<>();
contacts.add(new Contact("A","B",37));
contacts.add(new Contact("A","C",34));
contacts.add(new Contact("B","A",35));
Collections.sort(contacts, (Contact c1, Contact c2) -> {
int firstNameComparisonResult = c1.getFirstName().compareTo(c2.getFirstName());
if (firstNameComparisonResult != 0) {
return firstNameComparisonResult;
} else {
return c1.getLastName().compareTo(c2.getLastName());
}
});
System.out.println(contacts);
//[Contact{firstName='A', lastName='B', age=37}, Contact{firstName='A', lastName='C', age=34}, Contact{firstName='B', lastName='A', age=35}]
}
可能重复:http://stackoverflow.com/questions/1421322/我怎么做,我排序一个列表与多个排序参数。你的比较器也必须尊重姓氏。 –