当按钮单击我想要转到另一个xml布局文件时。 所以我写了如下开始新的活动。无法在android中启动活动
startActivity(new Intent(AndroidPHPConnectionDemo.this, MainActivity.class));
MainAcivity类,
public class MainActivity extends ListActivity implements FetchDataListener{
private ProgressDialog dialog;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
initView();
}
private void initView() {
// show progress dialog
dialog = ProgressDialog.show(this, "", "Loading...");
String url = "http://10.0.2.2/new/newA.php";
FetchDataTask task = new FetchDataTask(this);
task.execute(url);
}
@Override
public void onFetchComplete(List<Application> data) {
// dismiss the progress dialog
if(dialog != null) dialog.dismiss();
// create new adapter
ApplicationAdapter adapter = new ApplicationAdapter(this, data);
// set the adapter to list
setListAdapter(adapter);
}
@Override
public void onFetchFailure(String msg) {
// dismiss the progress dialog
if(dialog != null) dialog.dismiss();
// show failure message
Toast.makeText(this, msg, Toast.LENGTH_LONG).show();
}
}
所以主要活动课参考列表视图布局文件。当调试上面的代码时,执行startactivity行。但问题是活动不开始。这意味着我不能显示列表视图
请给答案克服这个问题
是否调用了'onCreate'?调用'onFetchComplete'吗? – m0skit0