我有两个if语句的for循环。它一切正常,除了我想添加通过第二个if语句的值传递给变量v1。我首先分配变量,然后变量充满了许多NA和我期待的三个值。但我只想要变量中的那三个值。R - 在两个语句之后将值写入变量
因此,不是只写满足要求的i
,而是将每个i
写入变量。
v1 <- c()
for(i in seq_along(y$values)){
if(y$lengths[i] < 500 && y$values[i] == TRUE){
y$values[i] <- FALSE
}
if(y$lengths[i] > 500 && y$values[i] == TRUE){
print(y$lengths[i])
v1[[i]] <- y$lengths[i]
}
}
我看看适用的功能,但无法真正弄清楚如何使用这两个如果陈述适用。
该数据是一个大的逻辑向量。我在该矢量上使用y <- rle(vec)
,这给我y$lengths
(1和几十万之间的所有数)和y$values
(真和假)。
期望的结果是RLE长度,其中> 500和真实是真实的:
[1] 5120
[1] 16630
[1] 10188
了打印命令给我就好了。
dput(y$length)
给我:
c(129719L, 1L, 79337L, 2L, 4L, 1L, 3L, 1L, 2L, 1L, 1L, 1L, 4L,
2L, 2L, 3L, 2L, 1L, 2L, 2L, 2L, 2L, 2L, 1L, 1L, 5L, 1L, 3L, 1L,
6L, 1L, 5120L, 1L, 39L, 1L, 12L, 1L, 121L, 1L, 14L, 1L, 6L, 1L,
3L, 1L, 3L, 1L, 2L, 1L, 6L, 1L, 11L, 1L, 9L, 1L, 10L, 2L, 6L,
1L, 2L, 2L, 1L, 1L, 7L, 2L, 4L, 1L, 2L, 1L, 4L, 1L, 3L, 2L, 5L,
1L, 5L, 4L, 8L, 1L, 4L, 1L, 4L, 2L, 2L, 2L, 9L, 1L, 2L, 1L, 2L,
1L, 3L, 2L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 1L, 3L, 3L, 1L,
7L, 1L, 1L, 1L, 1L, 2L, 6L, 2L, 2L, 1L, 2L, 4L, 3L, 1L, 1L, 1L,
4L, 3L, 2L, 1L, 5L, 5L, 2L, 2L, 3L, 1L, 2L, 1L, 1L, 1L, 2L, 1L,
4L, 2L, 2L, 1L, 1L, 1L, 4L, 1L, 1L, 3L, 4L, 2L, 1L, 1L, 13L,
1L, 3L, 2L, 3L, 1L, 9L, 1L, 1L, 1L, 1L, 2L, 3L, 1L, 4L, 1L, 13L,
1L, 3L, 1L, 4L, 1L, 8L, 1L, 7L, 1L, 2L, 1L, 2L, 1L, 2L, 1L, 3L,
1L, 4L, 1L, 2L, 2L, 5L, 1L, 1L, 2L, 2L, 1L, 1L, 1L, 1L, 4L, 3L,
3L, 2L, 1L, 1L, 2L, 1L, 1L, 2L, 3L, 1L, 2L, 1L, 4L, 1L, 9L, 2L,
6L, 1L, 14L, 1L, 2L, 1L, 6L, 1L, 16630L, 7L, 1L, 3L, 2L, 3L,
1L, 4L, 3L, 4L, 1L, 1L, 2L, 7L, 1L, 1L, 1L, 1L, 1L, 8L, 1L, 5L,
1L, 6L, 1L, 1L, 3L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 1L, 2L, 1L, 2L,
1L, 1L, 1L, 6L, 1L, 5L, 1L, 2L, 2L, 3L, 1L, 5L, 2L, 3L, 1L, 2L,
2L, 10L, 1L, 4L, 1L, 2L, 2L, 1L, 2L, 1L, 1L, 1L, 1L, 7L, 3L,
1L, 1L, 4L, 1L, 1L, 1L, 10L, 1L, 2L, 2L, 3L, 1L, 3L, 5L, 2L,
3L, 1L, 1L, 2L, 1L, 1L, 3L, 1L, 4L, 3L, 1L, 1L, 1L, 1L, 2L, 2L,
1L, 4L, 2L, 1L, 1L, 3L, 1L, 1L, 2L, 1L, 4L, 1L, 1L, 3L, 4L, 2L,
1L, 2L, 1L, 1L, 3L, 1L, 2L, 1L, 2L, 1L, 3L, 1L, 2L, 1L, 3L, 1L,
1L, 1L, 3L, 2L, 12L, 1L, 3L, 2L, 2L, 1L, 1L, 2L, 7L, 1L, 2L,
1L, 1L, 2L, 1L, 1L, 7L, 1L, 2L, 1L, 4L, 1L, 7L, 1L, 4L, 1L, 1L,
1L, 6L, 1L, 6L, 1L, 6L, 2L, 14L, 1L, 5L, 1L, 9L, 1L, 1L, 1L,
1L, 2L, 39L, 1L, 20L, 1L, 1L, 1L, 6L, 1L, 9L, 2L, 5L, 1L, 7L,
1L, 16L, 1L, 22L, 1L, 1L, 1L, 10L, 1L, 20L, 1L, 18L, 1L, 20L,
1L, 3L, 1L, 2L, 1L, 2L, 1L, 5L, 1L, 9L, 1L, 3L, 1L, 3L, 1L, 15L,
1L, 10L, 1L, 40L, 1L, 30L, 1L, 111L, 1L, 314L, 1L, 9L, 1L, 10188L,
4L, 88L, 1L, 8L, 1L, 1L, 1L, 1L, 1L, 15L, 1L, 24L, 1L, 1L, 2L,
3L, 1L, 16L, 1L, 3L, 1L, 4L, 2L, 2L, 2L, 1L, 2L, 5L, 2L, 2L,
7L, 1L, 1L, 3L, 2L, 3L, 7L, 2L, 1L, 1L, 6L, 1L, 4L, 2L, 2L, 1L,
2L, 1L, 1L, 1L, 13L, 1L, 2L, 1L, 2L, 1L, 3L, 1L, 3L, 1L, 4L,
1L, 16L, 1L, 4071L, 5L, 162912L, 1L, 6L, 1L, 280986L)
请'输入()'您的数据并包含所需结果的示例 –
仍然与你的问题混淆!你只想要那些大于500的y $长度? –
将'v1 [[i]] < - y $ lengths [i]'改为'v1 < - c(v1,y $ lengths [i])''。或者,更好的'y $长度[y $长度> 500]' – ExperimenteR