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正如我可以做,使孩子继承父不改变孩子的代码构造是这样的:的Javascript继承构造
var parent = function(params){
this.params = params;
}
var child = function(){}
var childObj = new child({one:1,two:2});
console.log(childObj.params) //should show params
您不能。您应该手动调用父方法(构造函数或泛型函数) – zerkms 2012-07-26 00:11:11