这通常不是客户端的问题。您的代码在行为上一致,但服务器响应可能会有所不同。
我跑你的代码几次,它抛出了一些问题:
>>> jsonurl = urlopen('http://www.reddit.com/r/funny/hot.json?limit=16')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)
File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 406, in open
response = meth(req, response)
File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 519, in http_response
'http', request, response, code, msg, hdrs)
File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 444, in error
return self._call_chain(*args)
File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 378, in _call_chain
result = func(*args)
File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 527, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 429: Unknown
你必须处理情况下,服务器的响应是什么,但HTTP 200可以在try
/except
包装您的代码块,并且只有当您的请求成功时,您才应该将jsonurl
传递给json.loads()。
另外urlopen返回一个类似文件的描述符。因此,如果您print jsourl
,它只是提供jsonurl.__repr__()
值。请看下图:
>>> jsonurl.__repr__()
'<addinfourl at 4393153672 whose fp = <socket._fileobject object at 0x105978450>>'
你要看看以下::
>>> jsonurl.getcode()
200
>>>
且仅当它200,你应该处理从该请求获得的数据。
谢谢你的回应非常丰富和乐于助人! – GangstaGraham