如何引用XSLT 2.0中的分组元素？

Question

我想组下面的XML文件：

<record> 
    <word>Hallo</word><translit>XUPPY</translit><gloss>gloss1</gloss> 
    <word>Bye</word><translit>EHS</translit><gloss>gloss2</gloss> 
    <word>Yes</word><translit>KGR</translit><gloss>gloss3</gloss> 
</record> 

所需的输出是

<s> 
    <set><word>Hallo</word><gloss>gloss1</gloss></set> 
    <set><word>Bye</word><gloss>gloss2</gloss></set> 
    <set><word>Yes</word><gloss>gloss3</gloss></set> 
</s> 

于是我就用for-each-group，如

<xsl:template match="record"> 
    <xsl:element name="s"> 
     <xsl:for-each-group select="*" group-starting-with="word"> 
      <xsl:element name = "set"> 
       <xsl:copy-of select="current-group()/word"/> 
       <xsl:copy-of select="current-group()/gloss"/> 
      </xsl:element> 
     </xsl:for-each-group> 
    </xsl:element> 
</xsl:template> 

不过，我得到这个输出，即，空群：

<s><set/><set/><set/></s> 

所以我在引用组中的元素时做错了什么。但是什么？我相信它一定是简单的。

Answer 1

word和gloss是成员当前组的，不儿童它。

尝试：

<xsl:template match="/record"> 
    <s> 
     <xsl:for-each-group select="*" group-starting-with="word"> 
      <set> 
       <xsl:copy-of select="current-group()[self::word or self::gloss]"/> 
      </set> 
     </xsl:for-each-group> 
    </s> 
</xsl:template> 

Answer 2

的current-group()给你组中的所有元素，如果你想选择一个特定的元素使用current-group()[self::gloss]。

我会

<set> 
    <xsl:copy-of select="., current-group()[self::gloss]"/> 
</set>