看来我的代码不显示使用我的系统的编辑功能后,并按下保存/提交按钮后,查询我试图使用通过该网址的变量,并使用$ _GET只显示用户自己的帐户,我知道我的代码在Mysql的更新语句周围有冲突,请大家帮忙。更新语句使用变量
我的问题是:如何在按下表格中的保存按钮后显示查询?
这里是我的代码:?
<?PHP
include ("dbcon1.php");
// GET变量username通过URL
$username=$_GET['username'];
?>
<html>
<head>
</head>
<body>
<form method="post">
<table>
<?PHP
//只获取查询根据URL(edit2.php USERNAME = $ USERNAME)
$customerquery=mysql_query("select * from customerinfo where username='$username'");
$customerrows=mysql_fetch_array($customerquery);
?>
//形成具有用户信息
<tr><td>First name:</td><td><input type="text" name="fname" value="<?PHP echo $customerrows['fname'];?>"></td></tr>
<tr><td>Last name:</td><td><input type="text" name="lname" value="<?PHP echo $customerrows['lname'];?>"></td></tr>
<tr><td>Address:</td><td><input type="text" name="address" value="<?PHP echo $customerrows['address'];?>"></td></tr>
<tr><td>Contact Number:</td><td><input type="text" name="contactno" value="<?PHP echo $customerrows['contactno'];?>"></td></tr>
<tr><td>Username:</td><td><input type="text" name="username" value="<?PHP echo $customerrows['username'];?>"></td></tr>
<tr><td>Password:</td><td><input type="password" name="password" value="<?PHP echo $customerrows['password'];?>"></td></tr>
//保存按钮
<tr><td><input type="submit" name="submit" value="Save"></td></tr>
</table>
</form>
</body>
</html>
<?PHP
include('dbcon1.php');
include('dbcon.php');
//保存按钮按下时,更新表
if(isset($_POST['submit'])){
$username=$_GET['username'];
$fname=$_POST['fname'];
$lname=$_POST['lname'];
$address=$_POST['address'];
$contactno=$_POST['contactno'];
$username=$_POST['username'];
$password=$_POST['password'];
//更新表
mysql_query("update customerinfo set fname='$fname',lname='$lname',address='$address',contactno='$contactno',username='$username',password='$password' where username='$username'");
header("location:index5.php?username=$username");
}
?>
<table border='1'>
<?PHP
include('dbcon.php');
include('dbcon1.php');
//获取通过URL可变用户名
$username = $_GET['username'];
//显示当前登录 //表信息,关于用户的用户
$customerquery = mysqli_query($con,"SELECT * FROM customerinfo WHERE username = '$username'");
while($customerrows=mysqli_fetch_array($customerquery)){
?>
<tr>
<td>Id</td><td>First Name</td><td>Last Name</td><td>Address</td><td>Contact No</td <td>Username</td><td>Password</td><td>Edit</td>
</tr>
<tr>
<td><?PHP echo $customerrows['id'];?></td>
<td><?PHP echo $customerrows['fname'];?></td>
<td><?PHP echo $customerrows['lname'];?></td>
<td><?PHP echo $customerrows['address'];?></td>
<td><?PHP echo $customerrows['contactno'];?></td>
<td><?PHP echo $customerrows['username'];?></td>
<td><?PHP echo $customerrows['password'];?></td>
//编辑按钮
<td><input type="button" value="edit" onClick="window.location='edit2.php?username=<?php echo $username ?>'"></td>
</tr>
<?PHP } ?>
</table>
<a href="login1.php">Log-out</a>
尽我所知,你已经混合了'mysqli_ *'和'mysql_ *'函数。最有可能的问题。这两个不混合。 –
@ Fred-ii-那么先生,最好只使用mysqli或mysql? – eatmycode
只要你正确地消毒,这取决于你。但你不能混用它们。你的DB文件是什么样子的,他们都使用'mysql_ *'作为SQL函数,还是'mysqli_ *'? –