所以我试图创建一个单人Pong游戏。我能够让球从屏幕上反弹回来,但是当它击中左侧的墙时,它会再生,但不会移动。此外,当试图移动桨时,它只会像1像素一样向上移动,并且只会向下移动1个像素,然后它不会再向上或向下移动。这很难解释,所以这里是代码。Pygame Pong,Paddle只上下移动一次,再生后球不移动
import sys
import pygame
pygame.init()
size = width, height = 1000, 800
screenColor = 0, 0, 0
outline = 0, 0, 255
paddleOne = pygame.image.load("PONGPADDLE.png")
ball = pygame.image.load("Bullet.png")
ballRect = ball.get_rect()
paddleRect = paddleOne.get_rect()
speed = [1, 1]
paddleOne_x = 980
paddleOne_y = 400
FPS = 1000
fpsClock = pygame.time.Clock()
paddleOnePos_x = 0
paddleOnePos_y = 0
screen = pygame.display.set_mode(size)
while 1:
for event in pygame.event.get():
if event.type == pygame.QUIT:
sys.exit()
elif event.type == pygame.KEYDOWN:
if event.key == pygame.K_UP:
paddleRect.y += 10
if paddleRect.top > 0:
paddleRect.top = -1
if event.key == pygame.K_DOWN:
paddleRect.y -= 10
if paddleRect.bottom < 800:
paddleRect.top = +1
if event.type == pygame.KEYUP:
if event.key == pygame.K_UP:
paddleRect_y = 0
if event.key == pygame.K_DOWN:
paddleRect_y = 0
ballRect = ballRect.move(speed)
if ballRect.right > width:
speed[0] = -speed[0]
if ballRect.top < 0 or ballRect.bottom > height:
speed[1] = -speed[1]
if ballRect.left < 0:
ballRect = ball.get_rect()
elif ballRect.colliderect(paddleRect):
speed[1] = -speed[1]
paddleOne_y += paddleRect.bottom
paddleOne_y += paddleRect.top
screen.fill(screenColor)
screen.blit(paddleOne, (paddleRect.left, paddleRect.top))
# screen.blit(paddleOne, (paddleOne_x, paddleOne_y))
screen.blit(ball, ballRect)
pygame.draw.rect(screen, outline, ((0, 0), (width, height)), 5)
pygame.display.flip()
fpsClock.tick(FPS)
您的整个'if event.type == pygame.KEYUP:'块对我来说看起来很奇怪。 'paddleRect_y = 0'表示每次用户释放向上或向下按钮时,桨板将其位置重置到屏幕的顶部。所以我不觉得你的桨不会移动到任何地方。也许你正在尝试做一些事情,比如“当用户释放密钥时将paddle的_velocity_重置为零”? – Kevin
您的'if paddleRect.top> 0'和'if paddleRect.bottom <800:'条件似乎也有问题。如果您尝试进行边界检查,我认为您需要切换'<' with '>',反之亦然。 – Kevin