我正在处理比较查询,该比较查询将比较不同信用卡类型处理的内容与我们的POS服务实际处理的内容。我遇到了一个问题,如果某些卡类型未在特定日期处理任何付款,但可能已退款,我不会看到某些类型的行。 IE:没有用VISA购买,但签发了VISA退款,但由于没有购买,该行不显示,即使该类型退款。显示0为空行
这里是我的查询:
WITH tran_total AS (
SELECT CONCAT(c.id_str, ' - ', c.clinic_str) AS Clinics,
t.clinic,
c.xcharge_mid,
p.pay_desc,
CAST(t.time_ran AS date) AS tran_date,
CASE WHEN SUM(t.amount) <> 0 THEN SUM(t.amount) * - 1
ELSE 0.00 END AS collection
FROM dbo.transactions AS t INNER JOIN
dbo.clinic_master AS c ON t.clinic = c.clinic INNER JOIN
dbo.paytype AS p ON t.clinic = p.clinic AND t.paytype_id = p.paytype_id
WHERE (t.time_ran > GETDATE() - 10)
AND (t.paytype_id IS NOT NULL)
AND (p.pay_desc = 'Visa' OR
p.pay_desc = 'MasterCard' OR
p.pay_desc = 'American Express' OR
p.pay_desc = 'Discover')
GROUP BY c.id_str, c.clinic_str, t.clinic, c.xcharge_mid, p.pay_desc, CAST(t.time_ran AS date))
SELECT w.Clinics,
w.pay_desc,
w.tran_date,
w.collection,
CASE WHEN w.pay_desc = 'Visa' THEN (SUM(VI_pur) - SUM(VI_ref))
WHEN w.pay_desc = 'MasterCard' THEN (SUM(MC_pur) - SUM(MC_ref))
WHEN w.pay_desc = 'American Express' THEN (SUM(AX_pur) - SUM(AX_ref))
WHEN w.pay_desc = 'Discover' THEN (SUM(DI_pur) - SUM(DI_ref)) END AS xcharge
FROM tran_total AS w LEFT OUTER JOIN
dbo.xcharge AS x ON w.xcharge_mid = x.xcharge_mid AND w.tran_date = x.settle_date
GROUP BY w.Clinics, w.pay_desc, w.tran_date, w.collection
ORDER BY w.Clinics, w.tran_date
我想过围绕这种开关,并与来自xcharge
表的比较开始,但没有一个pay_desc
,可以轻松地连接这些如果事情被处理为错误的卡(选择了VISA,但发现扫描),那么我觉得行仍然会被遗漏。
我想要的是,即使SUM(t.amount)
没有值,每个pay_desc
都会出现在每个tran_date
之间。我已经试过一个案例陈述来完成这个没有任何运气。
编辑:我觉得这个问题更多是由于t.time_ran
变量。如果没有给定的pay_desc
的支付,那么也不会有t.time_ran
,有没有我可以做的函数来列出GETDATE() - 10和GETDATE()之间的某种东西,只需要t.time_ran
和x.settle_date
是否匹配该变量?
对此有何看法?在此先感谢
UPDATE:
我创建了一个日历表,个别日期,并曾尝试以下查询:
WITH tran_test AS(
SELECT cal.calendardate AS cd,
p.clinic,
p.pay_desc,
p.paytype_id
FROM calendar cal, paytype p
WHERE cal.calendardate BETWEEN GETDATE()-10 AND GETDATE()+1
AND (p.pay_desc = 'Visa' OR
p.pay_desc = 'MasterCard' OR
p.pay_desc = 'American Express' OR
p.pay_desc = 'Discover'))
SELECT w.cd,
CONCAT(c.id_str, ' - ', c.clinic_str) AS Clinics,
w.pay_desc,
ISNULL(SUM(t.amount)*-1, 0) AS collection,
CASE WHEN w.pay_desc = 'Visa' THEN (SUM(x.VI_pur) - SUM(x.VI_ref))
WHEN w.pay_desc = 'MasterCard' THEN (SUM(x.MC_pur) - SUM(x.MC_ref))
WHEN w.pay_desc = 'American Express' THEN (SUM(x.AX_pur) - SUM(x.AX_ref))
WHEN w.pay_desc = 'Discover' THEN (SUM(x.DI_pur) - SUM(x.DI_ref)) END AS xcharge
FROM tran_test w
INNER JOIN clinic_master c
ON (w.clinic=c.clinic)
LEFT OUTER JOIN transactions t
ON (t.clinic=w.clinic AND t.paytype_id=w.paytype_id AND CAST(t.time_ran AS date) = w.cd)
LEFT OUTER JOIN xcharge x
ON (w.cd=x.settle_date AND c.xcharge_mid=x.xcharge_mid)
GROUP BY w.cd, c.id_str, c.clinic_str, w.pay_desc
ORDER BY w.cd
然而,当我xcharge
列似乎我没有得到一个问题乘以随机间隔,我不知道为什么。
[SQL服务器:在查询中用0替换NULL]的可能重复(http://stackoverflow.com/questions/16840522/sql-server-replacing-null-with-0-in-a-query) – Laurel
谢谢你的链接,但我已经尝试过'ISNULL(SUM(t.amount)* - 1,0)AS集合'以及不显示行 –
的结果是'pay_desc' null? – Laurel