如何查找具有两列或更多列的mySQL数据库中的所有表格

Question

我想查找mySQL数据库中具有两列'zoneid'和'affiliateid'的所有表格。

如果我使用下面的查询，它会给我具有任一列的表格。我想找出表有两列

SELECT DISTINCT TABLE_NAME 
    FROM INFORMATION_SCHEMA.COLUMNS 
    WHERE COLUMN_NAME IN ('affiliateid','zoneid') 
     AND TABLE_SCHEMA='openx'; 

我试图像

SELECT DISTINCT TABLE_NAME 
    FROM INFORMATION_SCHEMA.COLUMNS 
    WHERE COLUMN_NAME IN ('affiliateid') AND COLUMN_NAME IN ('zoneid') 
     AND TABLE_SCHEMA='openx'; 

书面查询，但它不工作

Answer 1

SELECT DISTINCT TABLE_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE COLUMN_NAME ='affiliateid' union SELECT DISTINCT TABLE_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE COLUMN_NAME LIKE 'zoneid' 

或

SELECT DISTINCT TABLE_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE COLUMN_NAME ='affiliateid' union all SELECT DISTINCT TABLE_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE COLUMN_NAME LIKE 'zoneid' 

或类似于

SELECT DISTINCT TABLE_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE COLUMN_NAME LIKE '%affiliateid%' union all SELECT DISTINCT TABLE_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE COLUMN_NAME LIKE '%zoneid%' 

Answer 2

试试这个：

SELECT name FROM sysobjects WHERE id IN 
(SELECT id FROM syscolumns WHERE name = 'affiliateid') 
and id in 
(SELECT id FROM syscolumns WHERE name = 'zoneid') 

OR

select t.name 
from sys.tables t 
inner join sys.columns c on c.object_id=t.object_id 
where c.name in ('zoneid','affiliateid') 
group by t.name 
having count(distinct c.name) = 2 

Answer 3

可以使用。

SELECT table_schema, table_name, count(*) AS `Tcount` FROM INFORMATION_SCHEMA.`COLUMNS` 
WHERE `column_name` IN ('affiliateid','zoneid') 
GROUP BY table_schema, table_name 
HAVING `Tcount` = 2 

中，Tcount应该是平等的号码，你找列。如果是这样，那么你的表都需要的列

Answer 4

这个工作对我来说：

SELECT DISTINCT C1.TABLE_NAME 
FROM INFORMATION_SCHEMA.COLUMNS C1 
INNER JOIN INFORMATION_SCHEMA.COLUMNS C2 
ON C2.TABLE_NAME=C1.TABLE_NAME 
AND C1.COLUMN_NAME='zoneid' 
AND C2.COLUMN_NAME='affiliateid' 
AND C1.TABLE_SCHEMA='openx' AND C2.TABLE_SCHEMA='openx'