laravel 4 - 同一控制器功能上的两条路线

Question

我想做一些事情，我不知道它是否可行。

这里是我的routes.php文件

Route::get('mockups/user/skills/{skill}', 'MockupsController@user'); 
Route::get('mockups/user/tours/{tour}', 'MockupsController@user'); 
Route::get('mockups/user', 'MockupsController@user'); 

和我MockupsController @用户功能

public function user($skill=null,$tour=null){ 
    if($tour ==null && $skill != null) 
     return View::make('demo/mockups/user/public',array('skill'=>$skill)); 
    if($tour!=null && $skill ==null) 
     return View::make('demo/mockups/user/public',array('tour'=>$tour)); 
    return View::make('demo/mockups/user/public'); 

} 

，如果我得到的/mockups/user/tours/tour1网址，控制器调用demo/mockups/user/public视图不发送$tour变量。如何使它工作？

编辑

public function user($skill=null,$tour=null){ 
    echo var_dump($skill); 
    echo var_dump($tour); 
    die(); 
    if($tour ==null && $skill != null) 
     return View::make('demo/mockups/user/public',array('skill'=>$skill)); 
    if($tour!=null && $skill ==null) 
     return View::make('demo/mockups/user/public',array('tour'=>$tour)); 
    return View::make('demo/mockups/user/public'); 

} 

显示

string(5) "tour1" NULL 

Answer 1

我不明白为什么你在做这么复杂。为什么不只是做

Route::get('mockups/user/skills/{skill}', 'MockupsController@skills'); 
Route::get('mockups/user/tours/{tour}', 'MockupsController@tours'); 
Route::get('mockups/user', 'MockupsController@user'); 

public function skills($skill) 
{ 
    return View::make('demo/mockups/user/public',array('skill'=>$skill)); 
} 

public function tours($tour) 
{ 
    return View::make('demo/mockups/user/public',array('tour'=>$tour)); 
} 

public function user() 
{ 
    return View::make('demo/mockups/user/public'); 
}