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试图找出如何让焦项目总数* numberlist []在C和C++,下面是代码:长度 '的char * numberlist []' C和C++
const char* list_of_filename[] = {"One","Two","Three","Four","Five"};
试图找出如何让焦项目总数* numberlist []在C和C++,下面是代码:长度 '的char * numberlist []' C和C++
const char* list_of_filename[] = {"One","Two","Three","Four","Five"};
查找数组中的元素的数量的标准习惯用法
int num_items = sizeof(list_of_filename)/sizeof(list_of_filename[0]);
如何:
sizeof(list_of_filename)/sizeof(char*)
或者更一般地:
sizeof(list_of_filename)/sizeof(list_of_filename[0])
而不是重复以前的答案,你可能会认为'的sizeof(list_of_filename)/的sizeof(* list_of_filename)' – 2012-04-05 01:56:48
我想,答案在同一时间:)我个人比较喜欢'[0]'版本,所以我不会对其他版本的编辑感觉正确。尽管编辑它到您的答案虽然 - 我给了你upvote :) – 2012-04-05 02:02:10