DB2 SQL左连接表的帮助

Question

我有一个SQL查询这个样子，

select 
    t1.id as ID, 
    case when t2.field1 = 1102 then (t2.field3 - t2.field2) end as A, 
    case when t2.field1 = 1112 then (t2.field3 - t2.field2) end as B, 
    case when t2.field1 = 1113 then (t2.field3 - t2.field2) end as C, 
    case when t2.field1 = 1106 then (t2.field3 - t2.field2) end as D 
    from table1 t1 
    left join table2 t2 
    on t1.id = t2.id 

，结果是这样的;

ID A  B  C  D 
---- ------ ----- ----- ------ 
1773 100 NULL NULL NULL 
1773 NULL 120 NULL NULL 
1773 NULL NULL 200 NULL 
1773 NULL NULL NULL 60 

但我想显示这样的结果;

 ID A  B  C  D 
    ---- ------ ----- ----- ------ 
    1773 100 120 200 60 

我该如何重写查询？ thx为您的帮助..

Answer 1

只需使用sum()和group by id来压平：

select 
t1.id as ID, 
sum(case when t2.field1 = 1102 then (t2.field3 - t2.field2) end) as A, 
sum(case when t2.field1 = 1112 then (t2.field3 - t2.field2) end) as B, 
sum(case when t2.field1 = 1113 then (t2.field3 - t2.field2) end) as C, 
sum(case when t2.field1 = 1106 then (t2.field3 - t2.field2) end) as D 
from table1 t1 
left join table2 t2 on t1.id = t2.id 
group by 1; 

高效。简单。顺便提一下，max()或min()可以很好地工作。

这是可行的，因为您的数据只有一个每个字段有一个非空值的场合;任何聚合函数都可以从空值中选出一个值。

Answer 2

如何嵌套查询每个值？

select t1.id as ID,  
    (select t2.field3 - t2.field2 from table2 t2 
    where t1.id = t2.id and t2.field1 = 1102) as A,  
    (select t2.field3 - t2.field2 from table2 t2 
    where t1.id = t2.id and t2.field1 = 1112) as B,  
    (select t2.field3 - t2.field2 from table2 t2 
    where t1.id = t2.id and t2.field1 = 1113) as C,  
    (select t2.field3 - t2.field2 from table2 t2 
    where t1.id = t2.id and t2.field1 = 1106) as D,  
from table1 t1 

这是远远没有达到最佳，但它的工作原理