SQL多个记录

Question

我有源表，如下所示：

ID Status State_id 
X Active 1 
X Active 2 
X Active 3 
X Active 4 
Y Active 2 
Y Active 3 
Z Active 1 
Z Active 2 
Z Active 3 
A Active 2 
A Active 3 

我需要基于STATE_ID 2,3 2输出。

组1只有2,3 STATE_ID

ID Status 
Y Active 
A Active 

组2具有2,3

ID Status 
X Active 
Z Active 

Answer 1

/*Set 1*/ 
    select t1.id, t1.status 
    from table1 t1 
    where t1.state_id in (2, 3) /*ids you want */ 
    and t1.id not in ((
    select distinct t2.id 
    from table1 t2 
    where t2.state_id in (1, 4) /*ids you dont want*/ 
)) 
    group by t1.id, t1.status 

只需翻转ID可设置2

Answer 2

附加的状态ID，我认为它应该给你预期的结果。

更新 SqlFiddle

--Set 1 
SELECT id ,status 
FROM table1 
-- WHERE status='Active' 
GROUP BY id ,status 
HAVING COUNT(DISTINCT state_id) =count(DISTINCT CASE WHEN state_id IN (2,3) THEN state_id END) ; 

--Set2 
SELECT id ,status 
FROM table1 
GROUP BY id ,status 
HAVING COUNT(DISTINCT state_id)>count(DISTINCT CASE WHEN state_id IN (2,3) 
    THEN state_id END) 
AND COUNT(DISTINCT CASE WHEN state_id IN (2,3) THEN state_id END) =2; 

Answer 3

你可以使用这个脚本。

集1

SELECT 
    ID, Status 
FROM 
    @Tbl T 
GROUP BY 
    ID, Status 
HAVING 
    SUM(CASE WHEN State_id IN (2,3) THEN 1 ELSE 0 END) = 2 
    AND SUM(CASE WHEN State_id IN (2,3) THEN 0 ELSE 1 END) = 0 

结果：

ID Status 
---- ---------- 
A Active 
Y Active 

集2

SELECT 
    ID, Status 
FROM 
    @Tbl T 
GROUP BY 
    ID, Status 
HAVING 
    SUM(CASE WHEN State_id IN (2,3) THEN 1 ELSE 0 END) = 2 
    AND SUM(CASE WHEN State_id IN (2,3) THEN 0 ELSE 1 END) > 0 

结果：

ID Status 
---- ---------- 
X Active 
Z Active