以编程方式检索Google结果

Question

如何创建一个Java程序，将单词“Hello World”输入到Google中，然后从结果页面中检索HTML？我没有尝试使用Robot类。

Answer 1

URL url = new URL("http://www.google.com/search?q=hello+world"); 
url.openStream(); // returns an InputStream which you can read with e.g. a BufferedReader 

如果进行多次程序要求谷歌通过这种方式，他们将开始您重定向到“很抱歉，但你看起来像一个机器人”的页面相当快。

你可能会更好做的是使用谷歌的custom search api。

Answer 2

对于通过程序执行谷歌搜索，您将需要一个开发人员API密钥和自定义搜索引擎ID。您可以从下面的URL获取开发者API密钥和自定义搜索引擎ID。

https://cloud.google.com/console/project'>Google开发者控制台 https://www.google.com/cse/all'>Google自定义搜索

后你有两个密钥和id在下面的程序中使用它。使用您的密钥更改apiKey和customSearchEngineKey。

一步一步的信息，请访问 - http://www.basicsbehind.com/google-search-programmatically/

 

    import java.io.BufferedReader; 
    import java.io.InputStreamReader; 
    import java.net.HttpURLConnection; 
    import java.net.URL; 

    public class CustomGoogleSearch { 
     final static String apiKey = "AIzaSyAFmFdHiFK783aSsdbq3lWQDL7uOSbnD-QnCnGbY"; 
     final static String customSearchEngineKey = "00070362344324199532843:wkrTYvnft8ma"; 
     final static String searchURL = "https://www.googleapis.com/customsearch/v1?"; 

     public static String search(String pUrl) { 
      try { 
       URL url = new URL(pUrl); 
       HttpURLConnection connection = (HttpURLConnection) url.openConnection(); 
       BufferedReader br = new BufferedReader(new InputStreamReader(connection.getInputStream())); 

       String line; 
       StringBuffer buffer = new StringBuffer(); 
       while ((line = br.readLine()) != null) { 
        buffer.append(line); 
       } 
       return buffer.toString(); 
      } catch (Exception e) { 
       e.printStackTrace(); 
      } 
      return null; 
     } 
     private static String buildSearchString(String searchString, int start, int numOfResults) { 
      String toSearch = searchURL + "key=" + apiKey + "&cx=" + customSearchEngineKey + "&q="; 

      // replace spaces in the search query with + 
      String newSearchString = searchString.replace(" ", "%20"); 

      toSearch += newSearchString; 

      // specify response format as json 
      toSearch += "&alt=json"; 

      // specify starting result number 
      toSearch += "&start=" + start; 

      // specify the number of results you need from the starting position 
      toSearch += "&num=" + numOfResults; 

      System.out.println("Seacrh URL: " + toSearch); 
      return toSearch; 
     } 


     public static void main(String[] args) throws Exception { 

      String url = buildSearchString("BasicsBehind", 1, 10); 
      String result = search(url); 
      System.out.println(result); 

     } 
    }